Given:
Desmond deposits $ 50 monthly.
Yearly he deposits = $50×12 = $ 600
Rate of interest compounded monthly = 4.7%
To find the amount he will receive after 10 years and the rate of change the value of his account after 10 years.
Formula
where,
A be the final amount
P be the principal
r be the rate of interest
t be the time and
n be the number of times the interest is compounded.
Now,
Taking,
P = 600, r = 4.7, n = 12, t = 10 we get,
or,
or,
Now,
At starting he has $ 600
At the end of 10 years he will be having $ 959.1
So,
The amount of change in his account = $ (959.1-600) = $ 359.1
Therefore the rate of change =
= 59.85%
Hence,
a) His account will contain $ 959.1 after 10 years.
b) The rate of change in his account is 59.85% after 10 years.
Answer:
85.9 (to the nearest hundredth)
Step-by-step explanation:
1 radian = 180°/
Therefore, 1.5 radians = 1.5 x (180°/) = 270/ = 85.9 (to the nearest hundredth)
Answer: y =2x + 1
Step-by-step explanation: just use y=mx + b to find the equation
Answer:
y = 3x - 16
Step-by-step explanation:
I just graphed the slope and went down 3 over to the left 1 and I found 16 was the intercept