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1 year ago

Which of the following statement is true ?

Mathematics

1 answer:

Alexandra [31]1 year ago

4 0

The following statement is true is a) All the rhombuses are squares .

Given :

In contrast to a square, the lengths of all four sides of a rhombus are equal, the diagonals of a rhombus bisect each other, and all four angles of a rhombus are not equal to 90 degrees.

Parallelograms are not all squares. Parallelograms have equal length opposite sides, hence squares with all sides equal are parallelograms. Rhombuses are the only kites that fly.

Because a parallelogram contains two pairs of parallel sides, a trapezium is not a parallelogram. A trapezium, on the other hand, has only one pair of parallel sides.

Learn more about the square here:

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You might be interested in

Calculate limits x>-infinity<br> -2x^5-3x+1

Lera25 [3.4K]

Given:

The limit problem is:

$\lim_{x\to -\infty}(-2x^5-3x+1)$

To find:

The value of the given limit problem.

Solution:

We have,

$\lim_{x\to -\infty}(-2x^5-3x+1)$

In the function $-2x^5-3x+1$ , the degree of the polynomial is 5, which is an odd number and the leading coefficient is -2, which is a negative number.

So, the function approaches to positive infinity as x approaches to negative infinity.

$\lim_{x\to -\infty}(-2x^5-3x+1)=\infty$

Therefore, $\lim_{x\to -\infty}(-2x^5-3x+1)=\infty$ .

3 0

3 years ago

Metal A has a density of 12.7 g/cm3.

stira [4]

Using the given information, the density of metal B is 8.58 g/cm³

<h3>Calculating density </h3>

From the question, we are to determine the density of metal B

From the given information,

55 g of metal A is combined with metal B to create an alloy with mass 90 g

∴ Mass of metal B in the alloy = 90 g - 55 g = 35 g

Now, we will determine the volume of metal A in the alloy

Using the formula,

Density = Mass / Volume

∴ Volume = Mass / Density

Volume of metal A in the alloy = 55/12.7

Volume of metal A in the alloy = 4.33 cm³

Then, we will determine the volume of the alloy

Volume of the alloy = 90/10.7

Volume of the alloy = 8.41 cm³

∴ Volume of metal B in the alloy = 8.41 cm³- 4.33 cm³

Volume of metal B in the alloy = 4.08 cm³

Now, for the density of metal B

Density = mass / volume

Density of metal B = 35 / 4.08

Density of metal B = 8.58 g/cm³

Hence, the density of metal B is 8.58 g/cm³.

Learn more on Calculating density here: brainly.com/question/13986137

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5 0

2 years ago

Which graph shows the solution to the system of linear inequalities? x – 4y < 4 y < x + 1 Image for option 1 Image for opt

slava [35]

Answer:

The graph in the attached figure

Step-by-step explanation:

we have

$x-4y$ ----> inequality A

solve for y

$-4y$

$4y>x-4$

$y> (x/4)-1$

The solution of the inequality A is the shaded area above the dashed line

The slope of the dashed line is positive

The y-intercept is the point $(0,-1)$

The x-intercept is the point $(4,0)$

$y< x+1$ ----> inequality B

The solution of the inequality B is the shaded area below the dashed line

The slope of the dashed line is positive

The y-intercept is the point $(0,1)$

The x-intercept is the point $(-1,0)$

Using a graphing tool

The solution of the system of inequalities in the attached figure

7 0

3 years ago

The edges of the diameter of a circle are at (-1,2) and (3,-1). Write the equation of the circle in general form.

Y_Kistochka [10]

Answer:

(x-1)²+ (y-0.5)²=6.25

Step-by-step explanation:

<u>The standard form of equation of a circle is;</u>

(x-a)²+(y-b)²=r² where (a,b) are the center of the circle and r is the radius

<u>Finding the mid-point of the given points</u>

(-1,2) and (3,-1)⇒midpoint will be 1/2(x₁+x₂) , 1/2(y₁+y₂)

midpoint= {1/2(-1+3), 1/2(2+-1)}

midpoint=(1,0.5)

<u>Finding the radius r; the distance from the center to either of the given two points</u>

Apply the distance formula d=√ (x₂-x₁)² +(y₂-y₁)²

Taking (x₁,y₁) as (1,0.5) and (x₂,y₂) as (-1,2) then

d=√ (-1-1)² +(2-0.5)²

d= √ (-2)²+(1.5)²

d=√4+2.25⇒√6.25⇒2.5

r=2.5

<u>Equation of the circle</u>

(x-1)² + (y-0.5)²=2.5²

(x-1)²+ (y-0.5)²=6.25

3 0

3 years ago

How many planes can be drawn through any three noncollinear points?

RideAnS [48]

Answer:

1 plane

I hope this helps!

5 0

4 years ago