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coldgirl [10]
4 years ago
14

on a floor plan, a room measures 2 inches by 5 inches. if the scale is 1 inch = 4 feet, what is the actual size of the room?

Mathematics
1 answer:
Ira Lisetskai [31]4 years ago
4 0
The actual size of the room is 8 feet by 20 feet.

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How do you solve for(−5)^5(−5)^−6
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Answer:

-1/5

Step-by-step explanation:

We know that a^b * a^c = a^(b+c)

(−5)^5(−5)^−6

(-5) ^(5+-6)

(-5)^-1

We know that a^-b = 1/a^b

1/(-5)^1

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3 years ago
Write the equation of the given circle. Center (1,-5) Radius of 10
kozerog [31]
(x-1)^2 + (y+5)^2 =100
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3 years ago
Hello I need help with this immediately please see attached image thank you so much I will give Brainliest
erma4kov [3.2K]

Note that while the figure is made up of rectangle and parallelogram, then the area of this figure

A_{figure}=A_{rectangle}+A_{parallelogram}.

1. The area of rectangle is

A_{rectangle\ ABCF}=AB\cdot BC.

The vertices of rectangle are points A(-2,-2), B(0,-6), C(8,-2) and F(6,2). Then

AB=\sqrt{(-2-0)^2+(-2+6)^2}=\sqrt{4+16}=\sqrt{20}=2\sqrt{5},\\ \\BC=\sqrt{(8-0)^2+(-2+6)^2}=\sqrt{64+16}=\sqrt{80}=4\sqrt{5}.

Therefore,

A_{rectangle\ ABCF}=2\sqrt{5}\cdot 4\sqrt{5}=8\cdot 5=40\ un.^2

2. The area of parallelogram can be calculated using formula

A_{parallelogram\ FCDE}=\text{base}\cdot \text{height}.

The base of parallelogram is segment CD with length

CD=\sqrt{(8-8)^2+(3+2)^2}=\sqrt{25}=5

and the height has length 2 un. Then

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3. Now

A_{figure}=40+10=50\ un.^2

8 0
3 years ago
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