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vampirchik [111]
1 year ago
11

There are 6 squares and 15 triangles. What is the simplest ratio of squares to triangles?

Mathematics
2 answers:
Maslowich1 year ago
6 0

Answer:

\frac{2}{5}

Step-by-step explanation:

\frac{6}{15}  =  \frac{2}{5}

So 6 squares to 15 triangles equals 2 squares to 5 triangles.

Paladinen [302]1 year ago
3 0

Answer:

2:5

Step-by-step explanation:

Hello!

A ratio is written as a:b.

Since we are writing it as a ratio of squares to triangles, "a" would be squares, and "b" would be triangles.

  • a:b
  • \text{squares  :  triangles}
  • 6:15
  • 3(2):3(5)    \hookrightarrow Remove common factors
  • 2:5

The simplest form of the ratio is 2:5.

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Effectus [21]

Answer:

5+9+-23

Step-by-step explanation:

7 0
3 years ago
need help asap plzz.Solve the inequality. (x + 19 ≤ −5). (A)x ≤ −14 (B)x ≤ 24 (C)x ≤ −24 (D)x ≤ 14
Sindrei [870]

Answer:

C

Step-by-step explanation:

given

x + 19 ≤ - 5 ( isolate x by subtracting 19 from both sides )

x ≤ - 24 →  C

3 0
3 years ago
The question is Stephen read for 34 minutes on Monday and 45 minutes on Tuesday. Use breaking apart to find how many minutes Ste
user100 [1]
Breaking apart means that you just take the tens from each number, and the ones from each number, then add them up.


The tens from your numbers are:
30 from 34
40 from 45

The ones from your numbers are:
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Now, you have to add up the tens and ones separately.
30 + 40 = 70
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The answer: Stephen read for 79 minutes total.
7 0
3 years ago
Determine which system below will produce infinitely many solutions. (2 points)
disa [49]
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6 0
3 years ago
Find the standard deviation of 21, 31, 26, 24, 28, 26
Vesnalui [34]

Given the dataset

x = \{21,\ 31,\ 26,\ 24,\ 28,\ 26\}

We start by computing the average:

\overline{x} = \dfrac{21+31+26+24+28+26}{6}=\dfrac{156}{6}=26

We compute the difference bewteen each element and the average:

x-\overline{x} = \{-6,\ 5,\ 0,\ -2,\ 2,\ 0\}

We square those differences:

(x-\overline{x})^2 = \{36,\ 25,\ 0,\ 4,\ 4,\ 0\}

And take the average of those squared differences: we sum them

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And we divide by the number of elements:

\displaystyle \sigma^2=\dfrac{\sum_{i=1}^n (x-\overline{x})^2}{n} = \dfrac{69}{6} = 11.5

Finally, we take the square root of this quantity and we have the standard deviation:

\displaystyle\sigma = \sqrt{\dfrac{\sum_{i=1}^n (x-\overline{x})^2}{n}} = \sqrt{11.5}\approx 3.39

8 0
3 years ago
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