Question

A cash register contains $10 bills and $100 bills with a total value of $2010. If there are 30 bills total, then how many of each does the register contain? $10 bills

Answer 1

Answer:

there will be 19 $100 bills

and 11 $10 bills

Step-by-step explanation:

$100*19=1900\\10*11=110\\1900+110=2010$

Answer 2

Answer:

11

Step-by-step explanation:

Let x be how many $10 bills there are.

Let y be how many $100 bills there are

x + y = 30

x = 30 - y

10x + 100y = 2010

10(30 - y) + 100y = 2010

300 - 10y + 100y = 2010

-10y + 100y = 2010 - 300

90y = 1710

y = 1710 / 90

y = 19

x = 30 - 19

x = 11