Which is an equation of the line with a slope of 1/4 and a y intercept of -2

Susan bought 12 ounces of candy. How many pounds did she buy?<br> Show the proportions needed

DedPeter [7]

Answer:

If Susan bought 12 ounces that would equal to .75 pounds

Step-by-step explanation:

4 0

2 years ago

You receive two quarters, one dime, and four pennies back in change. Write the amount as a fraction in simplest form

Ahat [919]

$\frac{50}{100} = \frac{2}{4} = \frac{1}{2}$
$\frac{10}{100} = \frac{1}{10}$
$\frac{4}{100} = \frac{2}{50} = \frac{1}{25}$
$\frac{1}{2} = .50$
$\frac{1}{25} = .04$
$\frac{1}{10} = .10$

7 0

3 years ago

Read 2 more answers

If f(x) =1/4x+3, what is the equation for f^-1 (x)?

ser-zykov [4K]

4x - 12

You can get this by switch the f(x) and the x and then solving for the new f(x)

7 0

3 years ago

Assume that there is a 4% rate of disk drive failure in a year. a. If all your computer data is stored on a hard disk drive wit

kap26 [50]

Answer:

a) 99.84% probability that during a year, you can avoid catastrophe with at least one working drive

b) 99.999744% probability that during a year, you can avoid catastrophe with at least one working drive

Step-by-step explanation:

For each disk drive, there are only two possible outcomes. Either it works, or it does not. The disks are independent. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

4% rate of disk drive failure in a year.

This means that 96% work correctly, $p = 0.96$

a. If all your computer data is stored on a hard disk drive with a copy stored on a second hard disk drive, what is the probability that during a year, you can avoid catastrophe with at least one working drive?

This is $P(X \ geq 1)$ when $n = 2$

We know that either none of the disks work, or at least one does. The sum of the probabilities of these events is decimal 1. So

$P(X = 0) + P(X \geq 1) = 1$

We want $P(X \geq 1)$ . So

$P(X \geq 1) = 1 - P(X = 0)$

In which

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 0) = C_{2,0}.(0.96)^{0}.(0.04)^{2} = 0.0016$

$P(X \geq 1) = 1 - P(X = 0) = 1 - 0.0016 = 0.9984$

99.84% probability that during a year, you can avoid catastrophe with at least one working drive

b. If copies of all your computer data are stored on four independent hard disk drives, what is the probability that during a year, you can avoid catastrophe with at least one working drive?

This is $P(X \ geq 1)$ when $n = 4$

We know that either none of the disks work, or at least one does. The sum of the probabilities of these events is decimal 1. So

$P(X = 0) + P(X \geq 1) = 1$

We want $P(X \geq 1)$ . So

$P(X \geq 1) = 1 - P(X = 0)$

In which

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 0) = C_{4,0}.(0.96)^{0}.(0.04)^{4} = 0.00000256$

$P(X \geq 1) = 1 - P(X = 0) = 1 - 0.00000256 = 0.99999744$

99.999744% probability that during a year, you can avoid catastrophe with at least one working drive

7 0

3 years ago

In horizontal analysis the percent change is computed by: a. Subtracting the analysis period amount from the base period amount.

Sonja [21]

Answer:

b. Subtracting the base period amount from the analysis period amount, dividing the result by the base period amount, then multiplying that amount by 100%

Step-by-step explanation:

A percentage change can be computed from ...

((new amount) -(old amount))/(old amount) × 100%

This best matches the description of choice B.

_____

<em>Comment on the answer</em>

The formula offered in the question will show the "percent change" from 100 to 103 as 3. It is not 3; rather, it is 3%. The final multiplication must be by 100% in order to arrive at the proper number.

3 0

3 years ago