SA=2H(L+W)+LW for open box
20=2H(4+W)+4(W)
distribute
20=8H+2WH+4W
divide both sides by 2
10=4H+WH+2W
solve for 1 variable, pick W
10-4H=WH+2W
10-4H=W(H+2)
(10-4H)/(H+2)=W
V=LWH
subsitute 4 for V, subsitute H for H and (10-4H)/(H+2) for W
V=(4)(H)(10-4H)/(H+2)
V=(40H-16H²)/(H+2)
find max value
take deritivitive of this thing
V'=-16(H²+4H-5)/((H+2)²)
using sign chart
sign changes from positive to negative at H=1
so at H=1
find W
W=(10-4H)/(H+2)
W=2
the dimeionts are
length=4ft
width=2ft
height=1ft
(the volume is 8 cubic feet)
Which parabola?

Equation of the parabola
y - y1 = 4p(x - x1)
The Vertex of the parabola given is (0, 0) because it does not have the values of x1 and y1.
Then Vertex = (0,0)
-Look for two values of y to the left and two points to the right.
You can choose the points that you which
x y
-3 y = -(-3)^2 = -9
-1 y = -(-1)^2 = -1
0 y = -(0)^2 = 0
1 y = -(1)^2 = -1
3 y = -(3)^2 = -9
C is the answer ! Hope I’m correct
The equation is:
h ( t ) = - 16 t² + 60 t + 3
The toy rocket will reach the ground when: h ( t ) = 0
- 16 t² + 60 t + 3 = 0

t 1 = - 0.05
t 2 = 3.8
Answer:
C ) 3.80 s
It does not have a mode
Mode: is the number that appears the most
in this situation, no number appears more than once
hope this helps