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GenaCL600 [577]

3 years ago

15

The area of a rectangular wall of a barn is 70 square feet. its length is 4 feet longer than twice its width. find the length an

d width of the wall of the barn.

1 answer:

NNADVOKAT [17]3 years ago

5 0

Hhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhh

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Considering the sign up fee and monthly membership fee for a gym the equation c=30m+25 can be used to represent the total cost o

Naddik [55]

Answer:

$25

Step-by-step explanation:

Cost = 30 x months + 25

Every month you will pay 30$

At 0 months when you sign up substitute m=0

Cost = 30x 0 +25 = 0 +25 =25

7 0

2 years ago

if f(x)=2(x)^2+5sqrt(x+2), complete the follwoing statement ( round your answer to the nearest hundreth) : f(0)=_____

Maslowich

Answer:

$f(0)=7.07$

Step-by-step explanation:

We have the function $f(x)=2(x)^2+5\sqrt{(x+2)}$

In this case we want to find the value of f0)

To find f(0) you must replace the x in the function with the number 0 and solve as shown below

$f(0)=2(0)^2+5\sqrt{(0+2)}$

$f(0)=0+5\sqrt{(0+2)}$

$f(0)=5\sqrt{(2)}$

Therefore

$f(0)=7.07$

5 0

3 years ago

Offering 15 points for a good and explained answer.

Romashka [77]

The answer is False

3 0

2 years ago

Kevin and Randi have a jar containing 63 coins , being either quarters or nickels . they total

Softa [21]

Yess, such fun so

q=number of quarter
n=number of nickles
q+n=63

9.15=915 cents
25 cents=1 q
5 cents=1 n so

915=25q+5n
915=5(5q+n)
divide by 5
183=5q+n

we also have q+n=63
subtract q from both sides
n=63-q
subsitute 63-q for n in second equation
183=5q+63-q
add like terms
183=4q+63
subtract 63 from both sides
120=4q
divdie by 4
30=q
there were 30 quarters
subsitute
63=30+n
subtract 30
33=n

30 quarters
33 nicles

8 0

2 years ago

PLEASE HELP ASAP!!!

EleoNora [17]

<span>Part 1:

$(x+1)^2-3(x+2) \\ \\ =x^2+2x+1-3x-6 \\ \\ =x^2-x-5$

option b.

Part 2:
$(5x^3y^{-3})(-6x^4y)\\ \\=5(-6)x^{3+4}y^{-3+1}\\ \\=-30x^7y^{-2}\\ \\=\frac{-30x^7}{y^2}$

option d

Part 3:
$\frac{8+x}{2} - \frac{x+3}{3} =4$

Multiply through by the LCM of 2 and 3 (i.e. 6)
$6\left(\frac{8+x}{2}\right) - 6\left(\frac{x+3}{3}\right) =6(4) \\ \\ 3(8+x)-2(x+3)=24 \\ \\ 24+3x-2x-6=24 \\ \\ x+18=24 \\ \\ x=24-18=6$

option b

Part 4
x^2-3x-8=x+4

$x^2-3x-8=x+4 \\ \\ x^2-3x-x-8-4=0 \\ \\ x^2-4x-12=0 \\ \\ (x-6)(x+2)=0 \\ \\ x=6 \ or \ -2$

option d

Part 5
Joseph is solving the equation x^2+8x-4=0 using the technique completing the square.
x^2+8x-4=0
x^2+8x+?=4+?

In completeing the square method, you divide the coeficient of x by 2, square the result and add to both sides of the equation.

Therefore, he should add 16 to both sides because (8/2)^2=16.

option d.
</span>

5 0

3 years ago