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ArbitrLikvidat [17]
3 years ago
13

Stacy wishes to pay off a loan of $5688 in 36 months. How large will the monthly payments be?

Mathematics
2 answers:
MatroZZZ [7]3 years ago
4 0
$158/month. Just divide 5688 by 36, and that gives you the monthly payment.
laiz [17]3 years ago
3 0
5688 divided by 36 is 158, so the answer is 158. Without interest of course
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Identify the solution of the inequality |4x − 2| > 14 and the graph that represents it.
kodGreya [7K]

The solution to the inequality |4x − 2| > 14 is x > 4 and x < -3

<h3>What is an inequality?</h3>

An inequality is an expression that shows the non equal comparison of two or more numbers and variables.

Given the inequality:

|4x − 2| > 14

Hence:

4x - 2 > 14 or -(4x - 2) > 14

x > 4 or x < -3

The solution to the inequality |4x − 2| > 14 is x > 4 and x < -3

Find out more on inequality at: brainly.com/question/24372553

4 0
2 years ago
Thanks if you help.....
marissa [1.9K]

Answer:

I'm guessing it's D.

Step-by-step explanation:

Sorry if wrong :> Hope i helped! Have a awesome day!!! You're a great hooman ^_^ Please mark brainliest !!

5 0
2 years ago
Help mmmmeeeeeeeeeeeeeeeeeee<br> will give 50 points!!!!
Likurg_2 [28]

For the above graph :

  • f (-4) = 1

  • f (2) = -5

  • f (0) = -3
4 0
3 years ago
Year Cash Flow (A) Cash Flow (B)
jeka57 [31]

Answer:

2.46

3.63

195,929.85

236,551.79

35.39

34.31

B

Step-by-step explanation:

Explaining it is kind of akward, but I can explain if you want.

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4 0
3 years ago
A quality-conscious disk manufacturer wishes to know the fraction of disks his company makes which are defective. Step 2 of 2 :
const2013 [10]

Answer:

The 80% confidence interval for the population proportion of disks which are defective is (0.059, 0.079).

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the zscore that has a pvalue of 1 - \frac{\alpha}{2}.

Suppose a sample of 1067 floppy disks is drawn. Of these disks, 74 were defective.

This means that n = 1067, \pi = \frac{74}{1067} = 0.069

80% confidence level

So \alpha = 0.2, z is the value of Z that has a pvalue of 1 - \frac{0.2}{2} = 0.9, so Z = 1.28.

The lower limit of this interval is:

\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.069 - 1.28\sqrt{\frac{0.069*0.931}{1067}} = 0.059

The upper limit of this interval is:

\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.069 + 1.28\sqrt{\frac{0.069*0.931}{1067}} = 0.079

The 80% confidence interval for the population proportion of disks which are defective is (0.059, 0.079).

7 0
2 years ago
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