Answer:
The ball will be 84 feet above the ground 1.125 seconds and 4.5 seconds after launch.
Step-by-step explanation:
Statement is incorrect. Correct form is presented below:
<em>The height </em>
<em> of an ball that is thrown straight upward from an initial position 3 feet off the ground with initial velocity of 90 feet per second is given by equation </em>
<em>, where </em>
<em> is time in seconds. After how many seconds will the ball be 84 feet above the ground. </em>
We equalize the kinematic formula to 84 feet and solve the resulting second-order polynomial by Quadratic Formula to determine the instants associated with such height:

(1)
By Quadratic Formula:

,
The ball will be 84 feet above the ground 1.125 seconds and 4.5 seconds after launch.
2 yards = 6 feet
6 times 5 is 30
30 ft squared
Answer:
3rd
Step-by-step explanation:
I think thats how u fill it
Answer:
Step-by-step explanation:
1) elimination
2) elimination
3)add
4)subtract
5) Variable
6) add
7) eliminate
8) subtract
9) eliminate
10) adding
11) adding
12) 2
13)2
14) 0
15) (2 , 0)
16) (2 , 0)
17) solution
Answer:
y = 5.595090517 or approximately 5.6
Step-by-step explanation:
Tan47 = 6/y
y x Tan47/Tan47 = 6/Tan47
y = 5.595090517 or approximately 5.6