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svet-max [94.6K]
3 years ago
10

A rectangle has a base of 2 yd and a height of 5ft. find the area of the rectangle

Mathematics
2 answers:
kirill [66]3 years ago
6 0

Answer:

The area of rectangle(A) is given by:

A=lw                                                       ..... [1]

where,<em> l</em> is the length of the rectangle and <em>w</em> is the width of the rectangle respectively.

As per the statement:

A rectangle has a base of 2 yd and a height of 5 ft.

⇒w = 2 yd and l = 5 ft

Use conversion:

1 yard = 3 ft

then;

in 2 yard = 6 feet

⇒w = 6 feet

Substitute the given values in [1] we have;

A = 5 \times 6= 30 ft^2

Therefore, the area of rectangle is, 30 square ft.

allsm [11]3 years ago
4 0
2 yards = 6 feet
6 times 5 is 30
30 ft squared
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Answer:

  1.3363

Step-by-step explanation:

The basic idea here is to find an expression for the direction vector between a point on L1 and a point on L2. Then, solve for the points on L1 and L2 that make that vector perpendicular to both lines L1 and L2. (The dot product of direction vectors is zero.) The distance between the points found is the shortest distance between the lines.

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Let P be a point on L1. Then the parametric equation for P is ...

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The dot product of this and the two lines' direction vectors will be zero:

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  (3s+1-6t, 2s-1, 5s+1+t)·(3, 2, 5) = 0 = 38s -13t +6 . . . perpendicular to L2

The solution to these equations is ...

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Then (Q-P) becomes (94, -1551, 564)/1237, and its length is ...

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The distance between the two lines is about 1.3363 units.

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