Answer:
- 4/3 0r - 1 1/3 0r - 1.33333333 ( the 3 keeps repeating)
Step-by-step explanation:
I would suggest to use a table so....
x y
2 0
-1 4
from 0 to 4 you add 4
from 2 to -1 you subtract 3
so y/x
4/-3 = - 1 1/3 or - 1.333333
Hope this helped a little!
The answer is surely x3 ?
Answer:
40%
Step-by-step explanation:
The probability he misses at least one of the targets is 1 minus the probability that he hits all of the targets.
P = 1 − 0.95¹⁰
P = 1 − 0.599
P = 0.401
Rounded, there is a 40% chance he misses at least one target.
Answer:
X=3
Step-by-step explanation:
Move all terms to the left side and set equal to zero. Then set each factor equal to zero.
Answer:
Ok, let's calculate the number of possible outcomes:
First, let's see the events and the number of outcomes in each event:
Drawing a card --- 4 outcomes
Rolling a number cube ---- 6 outcomes.
The total number of outcomes will be equal to the product between the number of outcomes in each individual event, this is:
C = 4*6 = 24.
Now, suppose that you have a restriction like:
"What is the probability that you have an odd number in the number cube?"
Ok, let's do the same:
Drawing a card ---- 4 outcomes (the restriction does not affect this event)
Rolling a number cube ---- 3 outcomes (because there are only 3 odd numbers)
The number of combinations is:
C' = 4*3 = 12.
Then the probability will be the quotient between the number of outcomes that meet the condition and the total number of outcomes:
P = C'/C = 12/24 = 0.5