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vladimir2022 [97]
1 year ago
5

Hi, can you help me answer this question please, thank you!

Mathematics
1 answer:
slavikrds [6]1 year ago
5 0

Problem Statement

We are asked to find the critical t-value for a confidence level of 80% and sample size of 17.

Method

To solve this, we simply need to do two things:

1. Calculate the degrees of freedom:

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3.9
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405.6



8.7
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4 0
2 years ago
Evaluate ∫ e3x cosh 2x dx A. 1/2e5x + 1/2ex + C B. 1/10e5x + 1/5 x + C C. 1/10e5x + 1/2ex + C D. 1/4e3x + 1/2 x + C
goldfiish [28.3K]

∫ e^(3x)*(cosh(2x)dx

= ∫ [e^(3x)*(e^(2x)+e^(-2x))/2]dx

= ∫ [(e^(5x)+e^x)/2]dx

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6 0
3 years ago
a team of 10 players is to be selected from a class of 6 girls and 7 boys. match each scenario to its probability
mars1129 [50]

Step-by-step explanation:

The selection of r objects out of n is done in

many ways.

The total number of selections 10 that we can make from 6+7=13 students is  

thus, the sample space of the experiment is 286

A.  

"The probability that a randomly chosen team includes all 6 girls in the class."

total number of group of 10 which include all girls is C(7, 4), because the girls are fixed, and the remaining 4 is to be completed from the 7 boys, which can be done in C(7, 4) many ways.

P(all 6 girls chosen)=35/286=0.12

B.

"The probability that a randomly chosen team has 3 girls and 7 boys."

with the same logic as in A, the number of groups were all 7 boys are in, is  

so the probability is 20/286=0.07

C.

"The probability that a randomly chosen team has either 4 or 6 boys."

case 1: the team has 4 boys and 6 girls

this was already calculated in part A, it is 0.12.

case 2, the team has 6 boys and 4 girls.

there C(7, 6)*C(6, 4) ,many ways of doing this, because any selection of the boys which can be done in C(7, 6) ways, can be combined with any selection of the girls.  

the probability is 105/286=0.367

since  case 1 and case 2 are disjoint, that is either one or the other happen, then we add the probabilities:

0.12+0.367=0.487 (approximately = 0.49)

D.

"The probability that a randomly chosen team has 5 girls and 5 boys."

selecting 5 boys and 5 girls can be done in  

many ways,

so the probability is 126/286=0.44

Did this help??

8 0
2 years ago
In the figure, the slope of mid-segment DE is -0.4. The slope of segment AC is 0.4 -0.4 2 -2 .
mario62 [17]
Therefore, slope of line DC = slope of line AC = -0.4. 
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3 years ago
Solve for x. Round answer to the nearest tenth. Submit 20 27​
docker41 [41]

Answer: 115.6

Step-by-step explanation:

8 0
2 years ago
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