Tenths 43.5
hundredths 43.60
ones 44
Answer:
Step-by-step explanation:
From the given information; Let's assume that R should represent the set of all possible outcomes generated from a bit string of length 10 .
So; as each place is fitted with either 0 or 1

Similarly; the event E signifies the randomly generated bit string of length 10 does not contain a 0
Now;
if a 0 bit and a 1 bit are equally likely
The probability that a randomly generated bit string of length 10 does not contain a 0 if bits are independent and if a 0 bit and a 1 bit are equally likely is;

so ; if bits string should not contain a 0 and all other places should be occupied by 1; Then:
; 

Answer:
someone had the same exact question i just helped him on it sub 4 for x and 1 for h
Step-by-step explanation:
Answer:
No
Step-by-step explanation:
No function, because the same output can't have two different inputs.
Angle 1 = 30°
Angle 2 = 90°
⇒ Angle 3 = 60°
So, it's right triangle. We can set the length of one side and get all other sides.
So, we have 1 triangle. If there are 2 or more triangles with the same data, all the triangles will be congruent because of : <span>Two triangles are </span><span>congruent if </span>"<span>ASA: Two interior angles and the included side in a triangle have the same measure and length, respectively, as those in the other triangle</span><span>.</span>"