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Ira Lisetskai [31]

1 year ago

12

what is the equation of the line that passes through the point (-2, 14) and is perpendicular to the with the following equation?

y = -2/5x - 1

2 answers:

EleoNora [17]1 year ago

6 0

You can use the first formula or the second one it still going to give you the same answer unless you miss something.

Butoxors [25]1 year ago

4 0

Answer: the y = -2/5x - 1

Step-by-step explanation: hoped this help you two

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Solve for x and y<br><br> 2x+7=3y-1

zlopas [31]

To solve for x and y, isolate each variable and simplify your equation:

Solve for x:
2x+7=3y-1 (Subtract 7 on each side)
2x=3y-8 (Divide by 2 on each side)
x= $\frac{3y}{2} -4$

Solve for y:
2x+7=3y-1
2x+8=3y (Add 1 on each side)
$\frac{2x}{3} + \frac{8}{3}$ =y (Divide by 3)
y= $\frac{2x}{3} + \frac{8}{3}$

~I hope this helps!~

7 0

3 years ago

Does the point (–3, 4) satisfy the equation y = –2x + 5? Yes Or No

Mekhanik [1.2K]

Answer:

No

Step-by-step explanation:

y = -2x + 5

4 = -2(-3) + 5 - Substitute both x and y

4 = 6 + 5 - Simplify

4 ≠ 11

Hence, no, (-3, 4) doesn't statify the equation y = -2x + 5

6 0

3 years ago

Prove that (4n+1)^2(4n-1)^2 is a multiple of 8 for all integers of n.<br><br> thanks.

azamat

Answer: i think (4n+1)^2(4n-1)^2 isnt a multiple of 8 for all integers of n because:

(4n + 1)²(4n - 1)²

= [(4n + 1)(4n - 1)]²

= (16n² - 1)²

= 16².n².n² - 2.16.n² + 1

= 8n²(32n² - 4) + 1

can see 8n²(32n² - 4) is a multiple of 8 but 1 isnt a multiple of 8

=> (4n + 1)²(4n - 1)² isnt a multiple of 8 for all integers of n.

Step-by-step explanation:

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I think it’s 2(x+7)=3x

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42 is 21% of 200. This is because 200*0.21 = 42.

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4 years ago

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