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34kurt
3 years ago
5

Solve for x and y 2x+7=3y-1

Mathematics
1 answer:
zlopas [31]3 years ago
7 0
To solve for x and y, isolate each variable and simplify your equation:

Solve for x:
2x+7=3y-1 (Subtract 7 on each side)
2x=3y-8 (Divide by 2 on each side)
x=\frac{3y}{2} -4

Solve for y:
2x+7=3y-1
2x+8=3y (Add 1 on each side)
\frac{2x}{3} + \frac{8}{3}=y (Divide by 3)
y=\frac{2x}{3} + \frac{8}{3}

~I hope this helps!~
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Is x^2-3x-23 polynomial
umka2103 [35]

Answer:

Yes

Step-by-step explanation:

6 0
2 years ago
Pleaseeee help me fast
jekas [21]
The growth is decaying, the original value is 500 and the common multiplier is 5, 500 divided by 5 turns to 100. 100/5=20. 20/5=4. x/5 or 1/5 if it has to be in a fraction format
8 0
3 years ago
Find the slope of a line parallel to a line that contains the points (8, -3) and (2, 5).
Illusion [34]

Answer:

-\frac{4}{3}(Your answer choices were really confusing, so I just put the plain answer)

Step-by-step explanation:

To find the slope of a line with just two points, we can use the formula \frac{y2-y1}{x2-x1}. In this case, \frac{5-(-3)}{2-8}. This is \frac{8}{-6}. This reduces to -\frac{4}{3}

8 0
1 year ago
What is the equation of the line passing through the points (2, -1) and (5.-10) in slope-intercept form
vagabundo [1.1K]

Answer:

y = -3x + 5

Step-by-step explanation:

Usually by drawing a simple graph, you can tell what the equation is, even if the graph isn't 100% accurate. From the points alone, you can tell that the slope is negative, since as you increase in x you decrease in y (which is a negative relationship). You can tell that it's +5 rather than -5 because the graph sketched shows that the line goes above 0 (indicating a positive number), rather than below (a negative number).

7 0
3 years ago
Sphere B is the image of sphere A after dilation by a scale factor of 44. If the surface area of sphere B is 432 km^2, find the
Sergeeva-Olga [200]
<h2>Answer:</h2>

27 km²

<h2>Step-by-step explanation:</h2>

SA=4\pi Jr^2

  4\pi r^2_B=432

      r^2_B=\frac{108}{\pi}

      r_B=\frac{6\sqrt3}{\sqrt{50}}

r_A=\frac{r_B}{4}=\frac{3\sqrt3}{2\sqrt\pi}

S_0SA=4\pi Y\begin{matrix}2\\A\\\end{matrix}

         =4\pi\bullet\frac{27}{4\pi}

         =27\ km

   Y_B:Y_A=4=1

  SA_B:SA_A=16:1

                 432\div 16=27\ km^2

                          simple\ relation.

<em>I hope this helps you</em>

<em>:)</em>

7 0
2 years ago
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