The motel revenue based on the number of rooms rented and group rental are as follows;
(a) The price for renting three rooms is $195
(b) The formula through which the unit rate of a room is found is aₙ = 71 - 3·(n -1)
(c) The function for the revenue, R(n) = 74·n - 3·n²
(d) The most amount that can be made is $456
The number of rooms that gives the most amount is 12 rooms
<h3>What is a revenue in business?</h3>
A revenue is the total amount received for the sale of goods and services
The number of rooms in the motel = 44
The price for renting one room = $71
The price for renting two rooms = $68
The per room group rate = $71 - $3 for each additional room
(a) The amount made if a family rents three rooms is given as follows;
The unit price for two rooms = $71 - $3 = $68
The unit price for three rooms = $68 - $3 = $65
The price for the three rooms is therefore;
$65 × 3 = $195
(b) The formula that gives the rate charged for each room to an organization is an arithmetic progression, which can be expressed as follows;
aₙ = a₁ + (n - 1)·d
Where;
n = The number of rooms the organization plans to rent
a₁ = The first term of the arithmetic progression = 71
d = The common difference = -3
Which gives;
aₙ = 71 - 3·(n - 1)
The price for each room when an organization rents <em>n</em> rooms is therefore;
aₙ = 71 - 3·(n - 1)
(c) The revenue for renting <em>n</em> room is given by the formula;
Revenue, R(n) = Unit rate × Number of rooms
∴ R(n) = (71 - 3·(n - 1)) × n = 74·n - 3·n²
(d) The -ve coefficient of n² in the formula with which the revenue can be found indicates that the function has a maximum value. The number of rooms that gives the most revenue is obtained at the from the derivative of the R(n) as follows;
R'(n) = 74 - 6·n = 0
n = 74/6 ≈ 12
Which gives;
= R(12) = 74 × 12 - 3 × 12² = 456
The maximum revenue from renting to a single group ≈ $456
The number of rooms to rent that gives the maximum revenue is <em>n</em> ≈ 12
Learn more about the maximum value of a function here:
brainly.com/question/3028708
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