3 years ago

How do i solve the question in the image provided ?

Mathematics

1 answer:

Mars2501 [29]3 years ago

6 0

Answer:

0.19+0.46i and 0.19-0.46i

Step-by-step explanation:

$\neq (-b+\sqrt{b^2-4ac} )/2a\\and\\(-b-\sqrt{b^2-4ac} )/2a\\\\a=8\\b=3\\c=2\\(-3+\sqrt{3^2-4*8*2} )/(2*8)\\= - 0.1875+0.463512i\\(-3-\sqrt{3^2-4*8*2} )/(2*8) = -0.1875-0.463512i$

hope its right

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