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DochEvi [55]
4 years ago
12

A small source radiates an electromagnetic wave with a single frequency into vacuum, equally in all directions. As the wave move

s, determine what happens to each of the following.
(a) frequency increases decreases remains constant
(b) wavelength increases decreases remains constant
(c) speed increases decreases remains constant
(d) intensity increases decreases remains constant
(e) amplitude of its electric field increases decreases remains constant
Mathematics
1 answer:
vlabodo [156]4 years ago
5 0

Answer:

a) Frequency remains constant

b) Wavelength remains constant

c) speed of the wave remains constant

d) Intensity decreases

e)  amplitude of its electric field decreases

Explanation:

a)  Frequency can be defined as the number of crests that pass a fixed point in the medium in unit time. It is the source of the wave that will determine the frequency. If the small source is changed to a bigger and faster one then the frequency will change. In our case, there is no change of source of wave, so the frequency remains constant.

b) The speed of of the wave is directly proportional to the wavelength. If we double the speed, the wavelength also doubles. Since the speed has not been doubled in our case, the wavelength will remain constant.

c) As indicated in b) since the wavelength is proportional to speed and it has not changed in our case, then the speed remains constant.

d) The intensity of a wave decreases as it moves further away from the source.

e) The intensity is related to the amplitude. Since the intensity decreases, the amplitude also decreases.

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Represent the number 108 in expanded form and exponent
lubasha [3.4K]

<h3>108 = 3³ × 2²</h3>

<h3>Further explanation</h3>

Let's recall following formula about Exponents and Surds:

\boxed { \sqrt { x } = x ^ { \frac{1}{2} } }

\boxed { (a ^ b) ^ c = a ^ { b . c } }

\boxed {a ^ b \div a ^ c = a ^ { b - c } }

\boxed {\log a + \log b = \log (a \times b) }

\boxed {\log a - \log b = \log (a \div b) }

<em>Let us tackle the problem!</em>

\texttt{ }

108 = 54 \times 2

108 = (27 \times 2) \times 2

108 = (9 \times 3) \times 2 \times 2

108 = (3 \times 3) \times 3 \times 2 \times 2

108 = 3^3 \times 2^2

\texttt{ }

<h3>Conclusion:</h3>

The number 108 could be represented in expanded form and exponent as following:

\boxed{ 108 = 3^3 \times 2^2 }

\texttt{ }

<h3>Learn more</h3>
  • Coefficient of A Square Root : brainly.com/question/11337634
  • The Order of Operations : brainly.com/question/10821615
  • Write 100,000 Using Exponents : brainly.com/question/2032116

<h3>Answer details</h3>

Grade: High School

Subject: Mathematics

Chapter: Exponents and Surds

Keywords: Power , Multiplication , Division , Exponent , Surd , Negative , Postive , Value , Equivalent , Perfect , Square , Factor.

#LearnWithBrainly

4 0
3 years ago
Assume that adults have IQ scores that are normally distributed with a mean of mu equals 100μ=100 and a standard deviation sigma
Ksivusya [100]

Answer:

51.60% probability that a randomly selected adult has an IQ between 86 and 114.

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 114, \sigma = 86

Find the probability that a randomly selected adult has an IQ between 86 and 114.

Pvalue of Z when X = 114 subtracted by the pvalue of Z when X = 86. So

X = 114

Z = \frac{X - \mu}{\sigma}

Z = \frac{114 - 100}{20}

Z = 0.7

Z = 0.7 has a pvalue of 0.7580

X = 86

Z = \frac{X - \mu}{\sigma}

Z = \frac{86 - 100}{20}

Z = -0.7

Z = -0.7 has a pvalue of 0.2420

0.7580 - 0.2420 = 0.5160

51.60% probability that a randomly selected adult has an IQ between 86 and 114.

3 0
4 years ago
9) Mrs. Jones spends $12.35 per day on her
Studentka2010 [4]

Answer:

Step-by-step explanation:

Since she buys lunch for 15 days you do 12.35 times 15 which is $185.25

5 0
3 years ago
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Need help ASAP.picture provides question
OLga [1]

Answer:

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Step-by-step explanation:

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igor_vitrenko [27]

Answer:24

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Step-by-step explanation:

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