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1 year ago

Can you write a real world problem for 2(3x+1)=14?

1 answer:

6 0

John and Paul want to go to the cinema, they know that the ticket costs $1 and each food box cost $3. If they spent $14, how many food boxes did each of them buy?

In this case since there is two people, we include that 2. 3x is representing the cost for buying x food boxes and 1 the cost for the ticket. 14 is the total amount of money spent.

$\begin{gathered} 2(3x+1)=!4 \\ 3x+1=7 \\ 3x=6 \\ x=2 \end{gathered}$

Each of them buy 2 food boxes.

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Given f (x) = 2 x + 9<br> f (x) = 15<br> x=

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3 years ago

What is the expanded form of 5³?

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A customer visiting the suit department of a certain store will purchase a suit with probability 0.22, a shirt with probability

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a. The probability that a customer purchase none of these items is 0.49

b. The probability that a customer purchase exactly 1 of these items would be of 0.28

Step-by-step explanation:

a. In order to calculate the probability that a customer purchase none of these items we would have to make the following:

let A represents suit

B represents shirt

C represents tie

P(A) = 0.22

P(B) = 0.30

P(C) = 0.28

P(A∩B) = 0.11

P(C∩B) = 0.10

P(A∩C) = 0.14

P(A∩B∩C) = 0.06

Therefore, the probability that a customer purchase none of these items we would have to calculate the following:

1 - P(A∪B∪C)

P(A∪B∪C) =P(A) + P(B) + P(C) − P(A ∩ B) − P(A ∩ C) − P(B ∩ C) + P(A ∩ B ∩ C)

= 0.22+0.28+0.30-0.11-0.10-0.14+0.06

= 0.51

Hence, 1 - P(A∪B∪C) = 1-0.51 = 0.49

The probability that a customer purchase none of these items is 0.49

b.To calculate the probability that a customer purchase exactly 1 of these items we would have to make the following calculation:

= P(A∪B∪C) - ( P(A∩B) +P(C∩B) +P(A∩C) - 2 P(A ∩ B ∩ C))

=0.51 -0.23 = 0.28

The probability that a customer purchase exactly 1 of these items would be of 0.28

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3 years ago

Which of the following statements is true if m∠E = m∠Y and m∠F = m∠X?

mars1129 [50]

Answer:

segment FE over segment XY equals segment EG over segment YZ equals segment GF over segment ZX

Step-by-step explanation:

see the attached figure to better understand the problem

we know that

If m∠E = m∠Y and m∠F = m∠X

then

Triangles EFG and YXZ are similar by AA Similarity Theorem

Remember that

If two figures are similar, then the ratio of its corresponding sides is proportional and its corresponding angles are congruent

In this problem

The corresponding sides are

FE and XY

EG and YZ

GF and ZX

so therefore

segment FE over segment XY equals segment EG over segment YZ equals segment GF over segment ZX Firstly , let us learn about trigonometry in mathematics.

Suppose the ΔABC is a right triangle and ∠A is 90°.

sin ∠A = opposite / hypotenuse

cos ∠A = adjacent / hypotenuse

tan ∠A = opposite / adjacent

Let us now tackle the problem!

A similar triangle has the same angle, in other words the triangle has the same shape but different sizes.

From the figure in the attachment , we can conclude that:

m∠E = m∠Y

m∠F= m∠X

m∠G = m∠Z

∴ ΔEFG ~ ΔYXZ ( ΔEFG is similar to ΔYXZ )

Because of the similarity , then:

FE : XY = EG : YZ = GF : ZX

Conclusion:

ΔFG is similar to ΔYXZ.

Segment FE over segment XY equals segment EG over segment YZ equals segment GF over segment ZX , i.e:

Keywords: Sine , Cosine , Tangent , Opposite , Adjacent , Hypotenuse , Triangle , Fraction , Lowest , Function , Angle

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3 years ago

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