Here is all I got for you. From the starting expression to the simplest one.
t^2 + 4tv + 4^2 =
t^2 + 4tv + 16 =
t(t + 4v) + 16
From April to December =9 months
the depreciation expense
3,600×(9÷12)=2,700
I believe the answer is 1/3
Answer:
$4956.23 approx
Step-by-step explanation:
Given data
P= $4860
R= 4%
T= 6 months = 0.5 years
Applying the compound interest formula we have
A=P(1+r)^t
Substitute
A=4860(1+0.04)^0.5
A= 4860(1.04)^0.5
A=4860*1.0198
A=4956.228
Hence the balance will be $4956.23 approx
Here are a few doubles facts:
5+5=10
2+2=4
3+3=6
A double is simply a pair of identical numbers added together. There's a pair of doubles you can <em>subtract </em>1 from to get 6+7, and there's a pair you can <em>add</em> 1 to get the same answer. What are those pairs?
Hint: If you take the example 3+4, you can either <em>subtract 1</em> from the double 4+4 or <em>add 1</em> to the double 3+3 to obtain your answer.
