We know that
[volume of a <span>pyramid]=[area of the base]*h/3
</span><span>a) The scale factor of the smaller pyramid to the larger pyramid in simplest form
</span><span>
12/20----------> 3/5
the answer Part a) is 3/5
</span><span>(b) The ratio of the area of the base of the smaller pyramid to the base of the larger pyramid
[</span>The ratio of the area of the base of the smaller pyramid to the base of the larger pyramid]--------> (3/5)²------> 9/25------> 0.36
[volume of a larger pyramid]=8192 cm³
h=20 cm
so
[8192]=[area of the base larger pyramid]*20/3
[area of the base larger pyramid]=8192*3/20------> 1228.80 cm²<span>
</span>[area of the base smaller pyramid]=(3/5)²*1228.80-----> 442.37 cm²
The ratio of the area of the base of the smaller pyramid to the base of the larger pyramid-----------> 442.37/1228.8--------> 0.36
0.36--------> is equal to (3/5)²
the answer part b) is 0.36
<span>(c) Ratio of the volume of the smaller pyramid to the larger
</span>
[Ratio of the volume of the smaller pyramid to the larger]=(3/5)³---> 27/125
27/125------> 0.216
the answer Part c) is 0.216
<span>(d) The volume of the smaller pyramid
[</span>The volume of the smaller pyramid]=0.216*8192------> 1769.47 cm³
<span>
the answer part c) is </span>1769.47 cm³<span>
</span>
Answer:
43 + 3.4 =46.4
Step-by-step explanation:
add it up
Answer:
a = 3
b = 2
c = 0
d = -4
Step-by-step explanation:
Form 4 equations and solve simultaneously
28 = a(2)³ + b(2)² + c(2) + d
28 = 8a + 4b + 2c + d (1)
-5 = -a + b - c + d (2)
220 = 64a + 16b + 4c + d (3)
-20 = -8a + 4b - 2c + d (4)
(1) + (4)
28 = 8a + 4b + 2c + d
-20 = -8a + 4b - 2c + d
8 = 8b + 2d
d = 4 - 4b
Equation (2)
c = -a + b + d + 5
c = -a + b + 4 - 4b+ 5
c = -a - 3b + 9
28 = 8a + 4b + 2c + d (1)
28 = 8a + 4b + 2(-a - 3b + 9) + 4 - 4b
28 = 6a - 6b + 22
6a - 6b = 6
a - b = 1
a = b + 1
220 = 64a + 16b + 4c + d (3)
220 = 64(b + 1) + 16b + 4(-b - 1 - 3b + 9) + 4 - 4b
220 = 60b + 100
60b = 120
b = 2
a = 2 + 1
a = 3
c = -3 - 3(2) + 9
c = 0
d = 4 - 4(2)
d = -4
Answer:
5(k + 1) and 5k + 5
Step-by-step explanation:
The easiest way to do this is to pick any number to substitute in for the variable <em>k </em>for ALL of the expressions, and find the expressions that equal the same as the first expression being compared.
For example, lets just make <em>k </em>equal 1 to make things easy. Plug 1 into <em>k</em> into the first expression. 2k + 2 + k + 3 + 2k → 2(1) + 2 + (1) + 3 + 2(1) = 10.
Now we do the same to the rest of the expressions and see which ones ALSO equal 10.
5(k + 1) → 5(1 + 1) = 10
5k + 5 → 5(1) + 5 = 10
5 + k^5 → 5 + (1)^5 = 6
5k^5 → 5(1)^5 = 5
