Answer:
The intersection is
.
The Problem:
What is the intersection point of
and
?
Step-by-step explanation:
To find the intersection of
and
, we will need to find when they have a common point; when their
and
are the same.
Let's start with setting the
's equal to find those
's for which the
's are the same.

By power rule:

Since
implies
:

Squaring both sides to get rid of the fraction exponent:

This is a quadratic equation.
Subtract
on both sides:


Comparing this to
we see the following:



Let's plug them into the quadratic formula:




So we have the solutions to the quadratic equation are:
or
.
The second solution definitely gives at least one of the logarithm equation problems.
Example:
has problems when
and so the second solution is a problem.
So the
where the equations intersect is at
.
Let's find the
-coordinate.
You may use either equation.
I choose
.

The intersection is
.
Answer:
3600
Step-by-step explanation:
perimeter is 120ft
Goal is to get the largest area.
so you can start with a list of possible solutions:
1*119 = 119ft
2*118 = 236ft
.
.
.
60*60 =3600ft
61*59 = 3599ft
.
.
Answer:
6:9
or 6 to 9
Step-by-step explanation:
Answer:1,331
Step-by-step explanation:put 121 on top and 11 on the bottom then start multiply , or you could use a calculator / Photo-math if you’re feeling lazy
Answer:
x=-3 x=-1 x=2 x=-2
Step-by-step explanation:
p(x) = (x^2 + 4x + 3)(x^2 – 4)
Set this equal to zero to find the x intercepts
0 = (x^2 + 4x + 3)(x^2 – 4)
Using the zero product property
(x^2 + 4x + 3) =0 (x^2 – 4) =0
Factor
(x+3)(x+1) =0 (x-2) (x+2)=0
Using the zero product property
x+3 =0 x+1 =0 x-2 =0 x+2 =0
x=-3 x=-1 x=2 x=-2