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2 years ago

Rewrite as a simplified fraction. \large{0.8\overline{95} = {?}}0.8 95 =?

Mathematics

1 answer:

k0ka [10]2 years ago

8 0

0.895 with 95 repeating on and on as a simplified fraction can be re-written as 887/990.

<h3>How to determine the fractional equivalent of this repeating decimal?</h3>

By critically observing the given number, we can reasonably and logically deduce that it has three (3) repeating digits. Since this number has three (3) repeating digits, we would have to multiply n by 1000 as follows:

1000n = 0.895

1000n = 895.95 .......equation 1.

10n = 8.95 .......equation 2.

Subtracting equation 2 from equation 1, we have:

1000n - 10n = 895.95 - 8.95

990n = 887

Dividing both sides by 990, we have:

n = 887/990

Simplified fraction, n = 887/990.

Read more on repeating decimal here: brainly.com/question/16727802

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Complete Question:

Write 0.895 with 95 repeating on and on as a simplified fraction.

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3 years ago

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Use number line to show numbers in the solution set of the inequality 2s+ 36 greater than 50.

Tems11 [23]

s>7

So, all values greater than 7 are included in the number line.

Step-by-step explanation:

We need to use number line to show numbers in the solution set of the inequality 2s+ 36 greater than 50

Solving and finding value of s:

2s+36>50

Adding -36 on both sides

2s+36-36>50-36

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The number line is shown in figure attached below

Keywords: Solving inequalities

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3 years ago

The manager of a warehouse would like to know how many errors are made when a product's serial number is read by

Inessa05 [86]

Answer:

14.625

Step-by-step explanation:

As per the situation the solution of mean and standard deviation change, based on all 12 samples is represented below:-

Mean of all 12 samples is shown below:-

$= \dfrac{Sum \ of \ all \ the \ observations}{Total \ number \ of \ observation}$

$= \dfrac{36+14+21+39+11+2+33+45+34+17+1+29}{12}$

So, the Mean = 23.5

and now,

The Standard deviation of all 12 samples is shown below:-

$= \sqrt{\frac{1}{12}} (36-23.5)^2+(14-23.5)^2+(21-23.5)^2+(39-23.5)^2+(11-23.5)^2+(2-23.5)^2+(33-23.5)^2+(45-23.5)^2+(34-23.5)^2+(17-23.5)^2+(1-23.5)^2+(29-23.5)^2}]$

$\sigma$ = 14.625

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3 years ago

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Natasha2012 [34]

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