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1 year ago

Hi are you able to solve it by using a step called exponential equations?

Mathematics

1 answer:

andriy [413]1 year ago

6 0

Given the equation:

$6^{2-3x}=6^{-2x-2}$

since both bases are 6, we can equate both exponents to get the following equation:

$2-3x=-2x-2$

solving for x, we get:

$\begin{gathered} 2-3x=-2x-2 \\ \Rightarrow-3x+2x=-2-2=-4 \\ \Rightarrow-x=-4 \\ \Rightarrow x=4 \end{gathered}$

therefore, the solution of the equation is x = 4

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What is the slope of the function?<br> –10<br> - 5<br> 5<br> 10

Eduardwww [97]

Answer:

Step-by-step explanation:

what is the function?

a slope going up means it is positive and a slope going down means it is negative

7 0

2 years ago

Find tan(a) in the triangle.<br> Choose 1 answer:<br> A. 7/25<br> B. 24/25 <br> C. 7/24 <br> D. 24/7

creativ13 [48]

Tan(a)= Toa

Toa =opposite/adjacent

Toa=7/25

final answer is 7/25

7 0

2 years ago

Read 2 more answers

Let X be a Bernoulli rv with pmf as in Example 3.18. a. Compute E(X2 ). b. Show that V(X) 5 p(1 2 p). c. Compute E(X79).

spayn [35]

The Bernoulli distribution is a distribution whose random variable can only take 0 or 1

The value of E(x2) is p
The value of V(x) is p(1 - p)
The value of E(x79) is p

<h3>How to compute E(x2)</h3>

The distribution is given as:

p(0) = 1 - p

p(1) = p

The expected value of x2, E(x2) is calculated as:

$E(x^2) = \sum x^2 * P(x)$

So, we have:

$E(x^2) = 0^2 * (1- p) + 1^2 * p$

Evaluate the exponents

$E(x^2) = 0 * (1- p) + 1 * p$

Multiply

$E(x^2) = 0 +p$

Add

$E(x^2) = p$

Hence, the value of E(x2) is p

<h3>How to compute V(x)</h3>

This is calculated as:

$V(x) = E(x^2) - (E(x))^2$

Start by calculating E(x) using:

$E(x) = \sum x * P(x)$

So, we have:

$E(x) = 0 * (1- p) + 1 * p$

$E(x) = p$

Recall that:

$V(x) = E(x^2) - (E(x))^2$

So, we have:

$V(x) = p - p^2$

Factor out p

$V(x) = p(1 - p)$

Hence, the value of V(x) is p(1 - p)

<h3>How to compute E(x79)</h3>

The expected value of x79, E(x79) is calculated as:

$E(x^{79}) = \sum x^{79} * P(x)$

So, we have:

$E(x^{79}) = 0^{79} * (1- p) + 1^{79} * p$

Evaluate the exponents

$E(x^{79}) = 0 * (1- p) + 1 * p$

Multiply

$E(x^{79}) = 0 + p$

Add

$E(x^{79}) = p$

Hence, the value of E(x79) is p

Read more about probability distribution at:

brainly.com/question/15246027

5 0

2 years ago

Simplify the expression: z2 – z(z + 3) + 3z a. 2z2 + 6z b. z + 3 c. 6z d. 0

Mama L [17]

This stuff is way to hard

5 0

3 years ago

Opal made t-shirts. It cost $39 to print one shirt. It costs $75 for 10 shirts. Write an equation to represent the

RUDIKE [14]

Answer:

39 X 10=75

Step-by-step explanation:

‍♀️

4 0

2 years ago