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boyakko [2]
3 years ago
15

Can someone please help me in finding the area of this shape? (Also, this is the whole question, I didn't cut anything out)

Mathematics
2 answers:
Valentin [98]3 years ago
6 0
<span>I guess the answer is 96m square because you need to multiply length by width</span>
victus00 [196]3 years ago
5 0
To find the area, you have to find the area of 2 different shapes... because you have a rectangle that has a semicircle cut out of it, you have to first find the area of the whole rectangle, then subtract the area of the semicircle.  The area of the whole rectangle would be...

A= length x width
A = 12m x 8m = 96 m^2

Now we need to find the area of the semicircle.  C is the midpoint of the semicircle and since the circle fits perfectly in the width of the rectangle, we know it's diameter is 8m.

The area of a circle is found with the equation A = pi (r)^2 so the area of a semicircle is found with the equation

A = pi(r)^2 / 2

Since the diameter is 8m then the radius is 8/2 = 4m

Let's plug it into the equation

A = pi(r)^2 / 2
A = 3.14(4)^2 / 2
A = 25.12m^2

Now let's subtract the area of the semicircle from the area of the rectangle and we will be left with the shaded area.

96m^2 - 25.12m^2 =

70.88m^2
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Triangle ABC is a non-right triangle with Angle C = 117, a = 12, and b = 18. Find Angle B to the nearest tenth.
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Using the law of cosines and sines, the measure of angle B is: 38.4°.

<h3>What is the Law of Cosines and Sines?</h3>

Law of cosines is: c = √[a² + b² ﹣ 2ab(cos C)]

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Use the law of sines to find angle B:

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Learn more about the law of cosines on:

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