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Sara and Paul are on opposite sides of a building that a telephone pole fell on. The pole is leaning away from Paul at

r-ruslan [8.4K]

Answer:

a) See figure attached

b) $x = \frac{sin(124)}{sin(34)} 80.086 = 118.732 ft$

c) $h = 35 sin (59) = 30.0 ft$

So then the heigth for the building is approximately 30 ft

Step-by-step explanation:

Part a

We can see the figure attached is a illustration for the problem on this case.

Part b

For this case we can use the sin law to find the value of r first like this:

$\frac{sin(22)}{35 ft} =\frac{sin(59)}{r}$

$r= \frac{sin(59)}{sin(22)} 35 ft = 80.086ft$

Then we can use the same law in order to find the valueof x liek this:

$\frac{sin(124)}{x ft} =\frac{sin(34)}{80.086}$

$x = \frac{sin(124)}{sin(34)} 80.086 = 118.732 ft$

And that represent the distance between Sara and Paul.

Part c

For this cas we are interested on the height h on the figure attached. We can use the sine indentity in order to find it.

$sin (59) = \frac{h}{35}$

And if we solve for h we got:

$h = 35 sin (59) = 30.0 ft$

So then the heigth for the building is approximately 30 ft

5 0

3 years ago

Suppose the scale factor you will use to enlarge the map is 5:1. What is the approximate area of the park in your enlarged drawi

Sunny_sXe [5.5K]

Answer:

image ?

Step-by-step explanation:

4 0

3 years ago

PLEASE hELp ASAP WILL MARK BRAINLIEST!

raketka [301]

Answer:

Its b

Step-by-step explanation:

The number line is saying people spend 70 n below.

5 0

3 years ago

The service life of a battery used in a cardiac pacemaker is assumed to be normally distributed. A random sample of ten batterie

Fittoniya [83]

Answer:

The confidence interval is $25.16 < \mu < 26.85$

Step-by-step explanation:

From the question we are given a data set

25.5, 26.1, 26.8, 23.2, 24.2, 28.4, 25.0, 27.8, 27.3, and 25.7.

The mean of the this sample data is

$\= x = \frac{\sum x_i}{n}$

where is the sample size with values n = 10

$\= x = \frac{25.5+ 26.1+ 26.8+23.2+ 24.2+ 28.4+ 25.0+ 27.8+ 27.3+ 25.7}{10}$

$\= x = 26$

The standard deviation is evaluated as

$\sigma = \sqrt{\frac{\sum (x-\= x)}{n} }$

substituting values

$= \sqrt{\frac{ ( 25.5-26)^2, (26.1-26)^2, (26.8-26)^2, (23.2-26)^2}{10} }$

$\cdot \ \cdot \ \cdot \sqrt{\frac{ ( 24.2-26)^2, (28.4-26)^2+( 25.0-26)^2+ (27.8-26)^2+( 27.3-26)^2+( 25.7-26)^2}{10} }$

$\sigma = 1.625$

The confidence level is given as 90% hence the level of significance is calculated as

$\alpha = 100 -90$

$\alpha =10$ %

$\alpha = 0.10$

Now the critical values of $\frac{\alpha }{2}$ is obtained from the normal distribution table as

$Z_{\frac{\alpha }{2} } = 1.645$

The reason we are obtaining the critical values of $\frac{\alpha }{2}$ instead of $\alpha$ is because we are considering two tails of the area under the normal curve

The margin of error is evaluated as

$MOE = Z_{\frac{\alpha }{2} } * \frac{\sigma }{\sqrt{n} }$

substituting values

$MOE = 1.645 * \frac{1.625 }{\sqrt{10} }$

$MOE = 0.845$

The 90%, two sided confidence interval is mathematically evaluated as

$\= x - MOE < \mu < \= x + MOE$

$26 - 0.845 < \mu < 26 + 0.845$

$25.16 < \mu < 26.85$

Given that the lower and the upper limit is greater than 25 then we can assure the manufactures that the battery life exceeds 25 hours

5 0

3 years ago

Helllppppppppp

Lana71 [14]

Answer:

x = 45, y = 90

x = 60, y = 75

x = 25, y = 110

Step-by-step explanation:

8 0

3 years ago

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(4x² + 11x^4 + 6x^5) + (3x^5+ 9x² + 12x^4) ｡ﾟ(ﾟ´ω`ﾟ)ﾟ｡