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AURORKA [14]
3 years ago
5

Joseph borrowed a book from a library. The library charged a fixed rental for the book and a late fee for every day the book was

overdue. The expression below shows the charges Joseph paid for the book when he returned it x days after the due date: 2 + 0.25x What does the coefficient of the expression represent? The fixed rental for the book The total late fee for the book The late fee per day for the book The number of days the book was overdue
Mathematics
2 answers:
krok68 [10]3 years ago
6 0
The late fee per day for the book.

The late fee must have been 0.25 times the number of days late, in this case x.

2 must have been the fixed rental for the book.
Iteru [2.4K]3 years ago
3 0

Answer:

the late fee per day for the book got it right on my test

You might be interested in
If a diameter intersects a chord of a circle at a perpendicular, what conclusion can be made? The diameter and the chord are con
yarga [219]

Answer:

The chord is bisected ⇒ 3rd answer

Step-by-step explanation:

* Lets revise some facts in the circle to solve the problem

- A chord in a circle is the segments whose endpoints lie on the

 circumference of the circle

- A diameter of a circle is a chord passes through the center of the

 circle

- The diameter is the longest chord in the circle

- Any line passes through the center of the circle and perpendicular

 to a chord on the circle bisects it

* Lets solve the problem

∵ The diameter of the circle passes through the center of the circle

∵ The diameter intersects a chord of a circle at a perpendicular

∴ The diameter is perpendicular to the chord

∵ Any line passes through the center of the circle and perpendicular

  to a chord on the circle bisects it

∴ The diameter bisects the chord

* The chord is bisected

8 0
3 years ago
Read 2 more answers
Need help plz help me out thanks!
Elden [556K]

Answer:

I hope this helps!

Step-by-step explanation:

3y(5x+3)=15yx+9y

2y(2x+3)=4yx+6y

4y(x+2)=4yx+8y

3y(7x+2)=21yx+6y

6 0
3 years ago
Read 2 more answers
I need help , I don’t understand this
marta [7]
#2. First, we factor each polynomial. Then, if any terms on both the top and the bottom of the fraction match, they cancel out. So... we do just that. You end up with:

\frac{x(x-4)}{(x+9)(x-4)}

Notice there's an (x-4) on both top and bottom. So they cancel out. That leaves us with your answer of \frac{x}{(x+9)}

#3. We do the same thing as above then multiply and simplify. In the interest of space, I'll cut straight to some simplification. 

\frac{2(x+2)^{3} }{6x(x+2)} ( \frac{5}{(x-2)^{2} } )

Now we start cancelling. For the first fraction, there are 3 (x+2)'s on top and 1 on the bottom so we will cancel out the one on the bottom and leave 2 (x+2)'s on top. There are no more polynomials to cancel out so now we multiply across:

\frac{10(x+2)^{2} }{6x(x-2)^{2} }

10 and 6 share a GCF of 2 so we divide both of those by 2. This leaves us with the final answer of:

\frac{5(x+2)^{2} }{3x(x-2)^{2} }

#4. This equation introduces division and because of it, we must flip the second fraction to make the division sign into a multiplication symbol. Again for space, I'll flip the fraction and simplify in one step. 

\frac{3(x+2)(x-2)}{(x+4)(x-2)} ( \frac{x+4}{6(x+3)})

Now we do our cancelling. First fraction has (x - 2) in the top and bottom. They're gone. The first fraction has a (x + 4) on the bottom and the second fraction has one on the top. Those will also cancel. This leaves you with:

\frac{3(x+2)}{6(x+3)}

3 and 6 share a GCF of 3 so we divide both numbers by this. This leaves you with your final answer:

\frac{x+2}{2(x+3)}

#5. We are adding so we first factor both fractions and see what we need to multiply by to make the denominators the same. I'll do the former first. (10 - x) and (x - 10) are not the same so we multiply the first equation (top and bottom) by (x - 10) and the second equation by (10 - x). Because they will now have the same denominator we can combine them already. This gives us:

\frac{(3+2x)(x-10)+(13+x)(10-x)}{(10-x)(x-10)}

Now we FOIL each to expand and then simplify by combining like terms. Again for space, I'm just showing the result of this; you end up with:

\frac{x^{2}-20x+100}{(10-x)(x-10)}

Now we factor the top. This gives you 2 (x - 10)'s on top and one on bottom. So we just leave one on the top and cancel the bottom one out. This leaves you with your answer:

\frac{x+10}{10-x}

#6. Same process for this one so I won't repeat. I'll just show the work.

\frac{3}{(x-3)(x+2)} +  \frac{2}{(x-3)(x-2)} becomes

\frac{3(x-2) + 2(x+2)}{(x-3)(x+2)(x-2)} which equals

\frac{3x - 6 + 2x + 4}{(x-3)(x+2)(x-2)} giving you the final answer

\frac{5x - 2}{(x-3)(x+2)(x-2)}

#7. For this question we find the least common denominator to make the denominators match. For 5, x, and 2x, the LCD is 10x. So we multiply top and bottom of each fraction by what would make the bottom equal 10x. This rewrites the fraction as:

\frac{3x}{5} ( \frac{2x}{2x}) * ( \frac{5}{x}( \frac{10}{10}) -  \frac{5}{2x} ( \frac{5}{5}))

Simplify to get:

\frac{3x}{5}  * ( \frac{25}{10x})

After simplifying again, you end up with your final answer: 

\frac{3}{2}




8 0
3 years ago
3/8=r+2/3 PLease help im really lazy
stira [4]

Answer:

- 7/24

Step-by-step explanation:

Step 1:

3/8 = r + 2/3

Step 2:

9/24 = r + 16/24

Step 3:

9/24 - 16/24 = r

Answer:

- 7/24 = r

Hope This Helps :)

5 0
2 years ago
Read 2 more answers
Which of the following is not a
mamaluj [8]
B 7/8 shows division, not multiplication
6 0
3 years ago
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