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1 year ago

A machine factory makes two and one 4th pounds of nails in one and a half hours at what rate in

Mathematics

1 answer:

xxTIMURxx [149]1 year ago

5 0

The machine make nails at a rate of 8th pounds per hour

<h3>How to determine the rate of making machine?</h3>

From the question, the given parameters are:

Amount of pounds of nails = 4th pounds
Number of time = half an hour

The rate in pounds per hour the machine make nails is then calculated as

Rate of making nails = Amount of pounds of nail/Number of time

Substitute the known values in the above equation

So, we have

Rate of making nails = 4th pounds/0.5 hour

Evaluate

Rate of making nails = 8th pounds per hour

Hence, the rate of making nails is 8th pounds per hour

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If TR=11 ft, find the length of PS

Klio2033 [76]

Answer:

PS = 31.5 ft

Step-by-step explanation:

∠PTS = 180 - 16 = 154°

164°(π/180) = 41π/45 radians

PS = rθ = 11(41π/45) = 31.48573...

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2 years ago

The sum of two trinomials is always a trinomial?<br><br> True or False and why?

Amiraneli [1.4K]

True because it says the sum of 2 trinomials that my answer. hope I helped.

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2 years ago

Juan purchased an antique that had a value of \$200$200dollar sign, 200 at the time of purchase. Each year, the value of the ant

garri49 [273]

Answer:

<h2>The value of a is $(\frac{11}{10} )^{222}$ .</h2>

Step-by-step explanation:

At the time of purchase, the value of the antique is $200.

After one year the value will increase 10%.

Hence, after one year, the value of the antique will be $\frac{110}{100} \times200$ = 220.

Similarly, after two year, the value will be $200\times (\frac{110}{100} )^{2}$ .

Thus, 222 years after purchase, the value of the antique will be $200\times (\frac{110}{100} )^{222} = 200\times (\frac{11}{10} )^{222}$ .

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3 years ago

Find the lateral surface area.

sveta [45]

Answer:

900 yd²

Step-by-step explanation:

You can draw the pattern that would need to be folded to make the figure, then find the area of that pattern (or "net"). It consists of a rectangle 10 yards wide and 60 yards long, together with another that is 20 yards long and 15 yards wide. The total area is the sum of these ...

... area = (60 yd)(10 yd) + (20 yd)(15 yd)

... = 600 yd² +300 yd²

... = 900 yd²