Answer:
UMAMI I think may be the answer to your question
Answer:
There is some inforrmation that is missing in this question. It should read:
A container holds 50 electronic components, of which 10 are defective. If 6 components are drawn at random from the container, the probability that at least 4 are not defective is . If 8 components are drawn at random from the container, the probability that exactly 3 of them are defective is .
Answers
Part 1. 0.02
Part 2. 0.0375
Explanation
The probability is a chance of an event happening. It is calculated as;
probability = (Number of favourable outcome)/(Number of available outcome)
Part 1
6 are chosen at random. If 4 are not defective, then 2 are defective.
P(at least 4 are not defective) = 4/40 × 2/10
= 1/10 ×1/5
= 1/50
= 0.02
Part 2
8 are chosen at random. If 3 are defective, the 5 are not defective.
P(3 are defective) = 3/40 × 5/10
= 15/400
= 3/80
= 0.0375
Step-by-step explanation:
70
the answer for the problem in the pic is A i think
Answer:
V≈113.1
Step-by-step explanation:
V=πr2h
3=π·32·12
3≈113.09734
-8n+7=31
-8n+7-7=31-7
-8n=31-7
-8n=24
-8n÷(-8)=24÷(-8)
n=24÷(-8)
n=-24÷8
n=-3
