Answer:
90
Step-by-step explanation:
Start with changing 35% and 30% to a decimal.
35% = .35%
30% = .30%
Then multiply 105 by .30%. ( but don't put the percent sign in the calculator when multiplying)
105 x .30% = 31.5
Then you want to divide 31.5 by .35%
31.5 / .35% = 90
He has a 1/6 chance.
if there are two of 1-6 tiles each in separate bags, he has a chance (total) of 2/12 of getting a 2 and a . simplify the 2/12 to 1/6 and that is your answer.
(i hope D:)
The are 40320 ways in which the 5 indistinguishable rooks be can be placed on an 8-by-8 chess- board so that no rook can attack another and neither the first row nor the first column is empty
<h3 /><h3>What involves the
rook polynomial? </h3>
The rook polynomial as a generalization of the rooks problem
Indeed, its result is that 8 non-attacking rooks can be arranged on an 8 × 8 chessboard in r8.
Hence, 8! = 40320 ways.
Therefore, there are 40320 ways in which the 5 indistinguishable rooks be can be placed on an 8-by-8 chess- board so that no rook can attack another and neither the first row nor the first column is empty.
Read more about rook polynomial
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