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3 years ago

Please help!

1 answer:

6 0

Answer:
Choice A
1/17; no, they are dependent events

============================================

Explanation:

There are 13 spades and 52 cards total. So 13/52 = 1/4 is the probability of drawing one spade

If we do not replace the card we pull out, then the probability of another spade is 12/51 since there are 12 spades left out of 51 total.

Multiply the fractions 1/4 and 12/51 to get
(1/4)*(12/51) = (1*12)/(4*51) = 12/204 = 1/17

The two events are not independent because the second event (pulling out a second spade) depends entirely on what happens in the first event (pulling out a first spade). The fact that the probability is altered indicates we have dependent events.

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Point P is located at (−2, 7), and point R is located at (1, 0). Find the y value for the point Q that is located two over three

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Answer:

$y_Q=\dfrac{21}{5}=4.2$

Step-by-step explanation:

If the point Q that is located two over three the distance from point P to point R, then PQ:QR=2:3.

Use formula to find the coordinates of the point Q:

$x_Q=\dfrac{3x_P+2x_R}{3+2}\\ \\y_Q=\dfrac{3y_P+2y_R}{3+2}$

In your case, P(-2,7) and R(1,0), then

$x_Q=\dfrac{3\cdot (-2)+2\cdot 1}{3+2}=\dfrac{-4}{5}\\ \\y_Q=\dfrac{3\cdot 7+2\cdot 0}{3+2}=\dfrac{21}{5}$

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3 years ago

Thee population of a town, P(t), is 2000 in the year 2010. Every year, it increases by 1.5%. Write an equation for the populatio

steposvetlana [31]

Given:

In 2010, the population of a town = 2000

Every year, it increase by 1.5%

To find the equation P(t) which represents the population of this town t years from 2010.

Formula

If a be the original population of a town and it increases by b% every year, after t year the population will be

$a (1+\frac{b}{100} )^{t}$

Now,

Taking, a =2000, b = 1.5 we get,

$P(t) = 2000(1+\frac{1.5}{100} )^{t}$

or, $P(t) = 2000(1+0.015)^{t}$

Hence,

The population of this town t years from 2010 P(t) = $2000(1+0.015)^{t}$ , Option D.

7 0

3 years ago

Please help me do this problem! ‼️

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3 years ago

A survey of 700 adults from a certain region asked, "What do you buy from your mobile device?" The results indicated that 59%

Kryger [21]

Answer:

a) the test statistic z = 1.891

the null hypothesis accepted at 95% level of significance

b) the critical values of 95% level of significance is zα =1.96

c) 95% of confidence intervals are (0.523 ,0.596)

Step-by-step explanation:

A survey of 700 adults from a certain region

Given sample sizes $n_{1} = 400 and n_{2} = 300$

Proportion of mean $p_{1} = \frac{236}{400} = 0.59 and p_{2} = \frac{156}{300} = 0.52$

Null hypothesis H0 : assume that there is no significant difference between males and women reported they buy clothing from their mobile device

p1 = p2

Alternative hypothesis H1:- p1 ≠ p2

a) The test statistic is

$Z = \frac{p_{1} -p_{2} }{\sqrt{pq(\frac{1}{n_{1} }+\frac{1}{n_{2} )} } }$

where $p = \frac{n_{1}p_{1} +n_{2}p_{2} }{n_{1}+n_{2}}= \frac{400X0.59+300X0.52}{700}$

on calculation we get p = 0.56

now q =1-p = 1-0.56=0.44

$Z = \frac{p_{1} -p_{2} }{\sqrt{pq(\frac{1}{n_{1} }+\frac{1}{n_{2} )} } }\\ =\frac{0.56-0.52}{\sqrt{0.56X0.44}(\frac{1}{400}+\frac{1}{300} }$

after calculation we get z = 1.891

b) The critical value at 95% confidence interval zα = 1.96 (from z-table)

The calculated z- value < the tabulated value

therefore the null hypothesis accepted

conclusion:-

assume that there is no significant difference between males and women reported they buy clothing from their mobile device

p1 = p2

c) 95% confidence intervals

The confidence intervals are P± 1.96(√PQ/n)

we know that = $p = \frac{n_{1}p_{1} +n_{2}p_{2} }{n_{1}+n_{2}}= \frac{400X0.59+300X0.52}{700}$

after calculation we get P = 0.56 and Q =1-P =0.44

Confidence intervals are ( P- 1.96(√PQ/n), P+ 1.96(√PQ/n))

now substitute values , we get

( 0.56- 1.96(√0.56X0.44/700), 0.56+ 1.96(0.56X0.44/700))

on simplification we get (0.523 ,0.596)

Therefore the population proportion (0.56) lies in between the 95% of confidence intervals (0.523 ,0.596)

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3 years ago

Write an equation that is non-proportional.

elena-s [515]

Answer:

y = mx + b. When b ≠ 0, the relationship between x and y is nonproportional.

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2 years ago