A - area of a trapezoid;
a, b - two bases.
A = h * ( a + b ) / 2 / * 2 ( we have to multiply both sides by 2 )
2 A = h *( a + b )
2 A = h a + h b
h b = 2 A - h a
b = ( 2 A - h a ) / h
b = 2 A/h - a
Answer: D )
If a=c and b=c then a=c this is transitive property
Answer:
something
Step-by-step explanation:
Answer:
The answer is 21/22
Step-by-step explanation:
n/7=3/22
then you cross-multiply
we have 22n=21
divide both sides by 22 to make n the subject of formula
n=21/22
<h3>
Answers:</h3>
- ST = 23
- RU = 8
- SV = 5
- SU = 10
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Explanation:
Focus on triangles SVT and UVT.
They are congruent triangles due to the fact that SV = VU and VT = VT. From there we can use the LL (leg leg) theorem for right triangles to prove them congruent.
Since the triangles are the same, just mirrored, this means ST = UT = 23.
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Following similar reasoning as the previous section, we can prove triangle RVU = triangle RVS.
Therefore, RS = RU = 8
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SV = VU = 5 because RT bisects SU.
Bisect means to cut in half. The two smaller pieces are equal.
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SU = SV + VU = 5+5 = 10
Refer to the segment addition postulate.