Y+6=(3/2)*x-6
-(3/2)x+y=-12
(3/2)x-y=12
3x-2y=24
Fill your inequality in with the y and x provided and then do the math. (4, -1) would fill in like this (I will use brackets to indicate absolute value symbols, since there are none in the equation editor):
![-1\ \textgreater \ [4]-5](https://tex.z-dn.net/?f=-1%5C%20%5Ctextgreater%20%5C%20%5B4%5D-5)
The right side is in fact equal to the left side so that's not the answer. For (-1, -4):
![-4\ \textgreater \ [-1]-5](https://tex.z-dn.net/?f=-4%5C%20%5Ctextgreater%20%5C%20%5B-1%5D-5)
and these are also equal. Let's try C now (-4, 1):
![1\ \textgreater \ [-4]-5](https://tex.z-dn.net/?f=1%5C%20%5Ctextgreater%20%5C%20%5B-4%5D-5)
. The absolute vale of -4 is 4 so 4 - 5 = -1 which is, in fact, less than 1. So C is our answer.
(x, y ) → (- 1, 3 )
The solution to the system of equations is the point of intersection of the 2 lines
From the graph, that is (x, y ) → ( - 1, 3 )
We can confirm by solving algebraically
Since both equations express y in terms of x we can equate the right sides
- x + 2 = - 6x - 3 ( add 6x to both sides )
5x + 2 = - 3 ( subtract 2 from both sides )
5x = - 5 ( divide both sides by 5 )
x = - 1
substitute x = - 1 into either of the 2 equations for y-coordinate
y = - x + 2 = 1 + 2 = 3
solution is (x, y ) → (- 1, 3 )
I think it's 16.. idkk look it up on google
The first one is 4•7 I believe