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3 years ago

Which of the following is true about radiation from the sun?

1 answer:

6 0

This isn't a math question and should be in the science section. However, I will still answer the question. The answer is choice B.

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Here's a further breakdown

A. False. The radiation or energy from the sun can travel through air or else you wouldn't feel the sun's rays. Also, plant life wouldn't be alive without that energy going through the air.

B. True. The rays travel through a vacuum of space. If they couldn't travel through space, then the same problem comes up as in choice A: the issue of not feeling the sun's rays.

C. False. They rays have different frequencies. Because there are many wavelengths (see choice D below), this means there are different frequencies. Recall that f = 1/w where f is the frequency and w is the wavelength.

D. False. The rays are made of different wavelengths. The visible light portion is what we can see, though there is a lot more to the electromagnetic spectrum (eg: ultraviolet light).

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So once again, the answer is choice B

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The function is used to convert temperature from Celsius (C) to Fahrenheit (F). The function C(K) = K − 273.15 is used to conver

ANTONII [103]

Answer:

$F(k)= \frac{9}{5}(k - 273.15) + 32$

Step-by-step explanation:

Given

$F(c)= \frac{9}{5}c + 32$

$C(k) = k - 273.15$

Required

Function from K to F

This implies that, we calculate F(k)

Given that:

$F(c)= \frac{9}{5}c + 32$

Substitute c(k) for c

$F(c(k))= \frac{9}{5}c(k) + 32$

Substitute: $C(k) = k - 273.15$

$F(c(k))= \frac{9}{5}(k - 273.15) + 32$

Hence:

$F(k)= \frac{9}{5}(k - 273.15) + 32$

8 0

3 years ago

Find an equation for the tangent to the curve at the given point. y=x^2+2 ; (2, 6)

Zinaida [17]

1) Find the derivative $y'=2x$ and $y'(2)=2\cdot2=4$ .
2) The equation of the tangent line is $y=y'(x_0)(x-x_0)+y_0$ , so at point (2,6): $x_0=2 \\ y_0=6$ and
$y=4(x-2)+6$
$y=4x-2$ -the equation of the tangent line at point (2,6).

5 0

2 years ago

Read 2 more answers

Multiply.<br> 8u2y6.2u?y?<br> Simplify your answer as much as possible.

musickatia [10]

The answer is 99.2u squared y squared

3 0

3 years ago

A particular battery claims to have a mean life of 400 hours with a standard deviation of 30 hours. Approximately what percent o

Svetach [21]

Using the normal distribution, it is found that 25.14% of the batteries will last more than 420 hours.

<h3>Normal Probability Distribution</h3>

The z-score of a measure X of a normally distributed variable with mean $\mu$ and standard deviation $\sigma$ is given by:

$Z = \frac{X - \mu}{\sigma}$

The z-score measures how many standard deviations the measure is above or below the mean.

Looking at the z-score table, the p-value associated with this z-score is found, which is the percentile of X.

In this problem, we have that the mean and the standard deviation are given, respectively, by:

$\mu = 400, \sigma = 30$ .

The proportion of the batteries will last more than 420 hours is <u>one subtracted by the p-value of Z when X = 420</u>, hence:

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{420 - 400}{30}$

Z = 0.67

Z = 0.67 has a p-value of 0.7486.

1 - 0.7486 = 0.2514.

0.2514 = 25.14% of the batteries will last more than 420 hours.

More can be learned about the normal distribution at brainly.com/question/24663213

#SPJ1

3 0

1 year ago

What does 7/18 + 2/27=

victus00 [196]

The answer would be 25/54

4 0

3 years ago

Read 2 more answers