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3 years ago

Midpoint of the line segment (-1,5) (-8,-4)

Mathematics

2 answers:

Semenov [28]3 years ago

7 0

Answer:-4.5,0.5

Step-by-step explanation:midpoint =x1+x2/2, y1+y2/2

-1+-8/2=x,-4+5/2=y

-9/2=x,1/2=y

-4.5=x, 0.5=y

Lana71 [14]3 years ago

6 0

Answer:

(- $\frac{9}{2}$ , $\frac{1}{2}$ )

Step-by-step explanation:

Using the midpoint formula

Given 2 points (x₁, y₁ ) and (x₂, y₂ ), then midpoint is

( $\frac{x_{1}+x_{2} }{2}$ , $\frac{y_{1}+y_{2} }{2}$ )

with (x₁, y₁ ) = (- 1, 5) and (x₂, y₂ ) = (- 8, - 4), then midpoint

= ( $\frac{-1-8}{2}$ , $\frac{5-4}{2}$ )

= ( - $\frac{9}{2}$ , $\frac{1}{2}$ )

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2 years ago

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Answer:

Image attached

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3 years ago

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Marina86 [1]

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3 years ago

The average value of a function f over the interval [−2,3] is −6 , and the average value of f over the interval [3,5] is 20. Wha

Xelga [282]

Answer:

The average value of $f$ over the interval $[-2,5]$ is $\frac{10}{7}$ .

Step-by-step explanation:

Let suppose that function $f$ is continuous and integrable in the given intervals, by integral definition of average we have that:

$\frac{1}{3-(-2)} \int\limits^{3}_{-2} {f(x)} \, dx = -6$ (1)

$\frac{1}{5-3} \int\limits^{5}_{3} {f(x)} \, dx = 20$ (2)

By Fundamental Theorems of Calculus we expand both expressions:

$\frac{F(3)-F(-2)}{3-(-2)} = -6$

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We obtain the average value of $f$ over the interval $[-2, 5]$ by algebraic handling:

$F(5) - F(3) +[F(3)-F(-2)] = 40 + (-30)$

$F(5) - F(-2) = 10$

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2 years ago

What is the value of x in the equation 1/2x - 3/4 = 3/8 - 5/8

Kitty [74]

The answer

x = 1

step by step

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