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zimovet [89]
1 year ago
15

A minor league hockey team had the following scores for the start of the season for the start of the season 3,6,2,1,2,3,0,4,5,1,

5,4. If the hockey team scores 9 goals in their next game, would the mean, median or mode be more affected?

Mathematics
1 answer:
PolarNik [594]1 year ago
4 0

ANSWER

The mean will be the most affected.

EXPLANATION

Given;

3,6,2,1,2,3,0,4,5,1,5,4

Initially, the mean, median and mode is calculated thus;

\begin{gathered} mean=\frac{3+6+2+1+2+3+0+4+5+1+5+4}{12} \\ =\frac{36}{12} \\ =3 \\ mode=1,2,3,5 \end{gathered}

To calculate the median, we need to re-arrange in ascending order. Hence;

\begin{gathered} 0,1,1,2,2,3,3,4,4,5,5,6. \\ median=\frac{(3+3)}{2} \\ =\frac{6}{2}=3 \end{gathered}

After adding 9;

The new data is;

0,1,1,2,2,3,3,4,4,5,5,6,9

The new mean is;

\begin{gathered} mean=\frac{3+6+2+1+2+3+0+4+5+1+5+4+9}{13} \\ =3.46 \\ Mode=3 \\ median=3 \end{gathered}

The mean will be the most affected.

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