Triangle PQR is formed by connecting the midpoints of the side of triangle MNO. The lengths of the sides of triangle PQR are sho
wn. What is the length of MN? Figures not necessarily drawn to scale.
1 answer:
The length of segment found using properties of an equilateral triangle and segment addition postulate is 10
Segment addition postulate states that a line AC contains a point B if we have AB + BC = AC
The sides of ∆PQR are equal to 5, therefore, ∆PQR is an equilateral triangle
According to the mid segment theorem, we have;
RQ || MN
RQ = 0.5 × MN
RP || ON
RP = 0.5 × ON
PQ || MO
PQ = 0.5 × MO
Therefore, from alternate interior angles theorem, we have;
‹PRQ = ‹RPM
‹PQR = ‹QPN
‹QRP = ‹RQO
However, ‹PRQ = ‹PQR = ‹QPR = 60°, which gives;
∆MRP and ∆QPN are equilateral triangles of side length 5
From which we have;
MR = RP = MP = 5
PN = QN = PQ = 5
MN = MP + PN; Segment addition postulate
Therefore;
MN = 5 + 5 = 10
Learn more about segment addition postulate here:
#SPJ1
You might be interested in
Answer:
Part A:
( 1.8333, -0.08333)
Part B:
x = 2 or x = 5/3
Step-by-step explanation:
The quadratic equation
has been given.
Part A:
We are required to determine the vertex. The vertex is simply the turning point of the quadratic function. We shall differentiate the given quadratic function and set the result to 0 in order to obtain the co-ordinates of its vertex.
Setting the derivative to 0;
6x - 11 = 0
6x = 11
x = 11/6
The corresponding y value is determined by substituting x = 11/6 into the original equation;
y = 3(11/6)^2 - 11(11/6) + 10
y = -0.08333
The vertex is thus located at the point;
( 1.8333, -0.08333)
Find the attached
Part B:
We can use the quadratic formula to solve for x as follows;
The quadratic formula is given as,
From the quadratic equation given;
a = 3, b = -11, c = 10
We substitute these values into the above formula and simplify to determine the value of x;
