The length of segment found using properties of an equilateral triangle and segment addition postulate is 10
<h3>What is segment addition postulate?</h3>
Segment addition postulate states that a line AC contains a point B if we have AB + BC = AC
The sides of ∆PQR are equal to 5, therefore, ∆PQR is an equilateral triangle
According to the mid segment theorem, we have;
RQ || MN
RQ = 0.5 × MN
RP || ON
RP = 0.5 × ON
PQ || MO
PQ = 0.5 × MO
Therefore, from alternate interior angles theorem, we have;
‹PRQ = ‹RPM
‹PQR = ‹QPN
‹QRP = ‹RQO
However, ‹PRQ = ‹PQR = ‹QPR = 60°, which gives;
∆MRP and ∆QPN are equilateral triangles of side length 5
From which we have;
MR = RP = MP = 5
PN = QN = PQ = 5
MN = MP + PN; Segment addition postulate
Therefore;
MN = 5 + 5 = 10
Learn more about segment addition postulate here:
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