Plz help me Jen can jump rope 80 times in 60 seconds. If she jumps at a constant ratio of seconds to jumps, how many jumps can s
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Let's first rewrite it in vertex form.
Start by completing the square.
y = x² + 4x + 4 - 4 - 1
y = (x + 2)² - 5
(x + 2)² = y + 5
Now, 4a = 1; a =
So, the vertex form is (x + 2)² = 4()(y + 5)
So, we know that the vertex is at (-2, -5).
Since it's a concave up parabola, we just have to change the y-value to find the focus.
∴ F(-2, -5 +)
F(-2,
)
Start by completing the square.
y = x² + 4x + 4 - 4 - 1
y = (x + 2)² - 5
(x + 2)² = y + 5
Now, 4a = 1; a =
So, the vertex form is (x + 2)² = 4(
So, we know that the vertex is at (-2, -5).
Since it's a concave up parabola, we just have to change the y-value to find the focus.
∴ F(-2, -5 +
F(-2,
Let
x----------> charge per hour to rent a jet sky in dollars
y----------> the total cost to rent a jet sky in dollars
we know that
<u>First Jet Sky Company</u>
---------> equation
<u>Second Jet Sky Company</u>
---------> equation
we know that
To find the number of hours for which the costs are the same
equate equation and equation
The intersection both graphs is the solution of the problem
using a graph tool
see the attached figure
the intersection point is
That means
For
the cost of the rent is in both companies
therefore
<u>the answer is</u>
