Answer:
-31 (perhaps if I 100% knew what I was doing, but this is what I believe the answer should look like based on my research which consisted of me finding out the mechanics of such expressions from a website I found online)
Step-by-step explanation:
I have never had to solve a question like this, so my answer is to be taken with a grain of salt (bucket full).
When we see that funky symbol over there, we're going to want to do some funky things:
6
∑(-2k + 5)
k=3
So we'll substitute 3 for k, as seen here:
(-2(3) + 5)
But wait! We still got that 6, so we'll throw that in with the 3:
(-2(3 · 6) + 5)
From here, we PEMDAS or whatever you prefer until we're done!
(-2(18) + 5)
(-36 + 5)
(-31)
-31
[Processing ends successfully.. Just kidding, I ain't no robot!]
We use the fact that if x+y+z = 0, then x³+y³+ z³ = 3 x y z.<span>
(x</span>²-y²) + (y²-z²) + (z²-x²) = 0<span>
also: (x-y) + (y-z)+ (z-x) = 0
we assume that: x </span>≠y ≠ z.
<span>
hence,
(x²-y²)³ + (y²-z²)³ + (z²-x²)³ ÷ (x-y)³ + (y-z)³ + (z-x)³
= 3 (x</span>²-y²) (y²-z²) (z²-x²) ÷ [3 (x-y) (y-z) (z-x)]
<span>= (x+y) (y+z) (z+x)</span>
Answer:
x^5/6 + 2x^7/3.
Step-by-step explanation:
x^1/3 ( x^1/2 + 2x^2 )
= x^(1/3 + 1/2) + 2x^(1/3 + 2)
= x^5/6 + 2x^7/3
Answer:
so, i am pretty sure all this is saying is move the plot nine units down the y axis. so you'd plot (5, 7).
Step-by-step explanation:
i hope this helps, let me know if this is right.
