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gtnhenbr [62]
3 years ago
5

Write a sine function that has a midline of 5, an amplitude of 4 and a period of 3pi/2

Mathematics
1 answer:
soldi70 [24.7K]3 years ago
8 0

Answer:

Step-by-step explanation:

The standard form for this function is

y = Asin(Bx - C) + D where

A is the amplitude,

B is used to find the period in the formula period=\frac{2\pi}{B},

C is used to find the phase shift in the formula ps=\frac{C}{B},

and D is the midline which either moves the function up or down from its natural midline of 0.

We have no given phase shift, so there is no C value. The amplitude is easy; we just fill in A as 4. The period is another story:

\frac{3\pi}{2} =\frac{2\pi}{B} and we solve for B by cross multiplying:

3πB = 4π and

B=\frac{4\pi}{3\pi} so

B = \frac{4}{3} so the function is

y=4sin(\frac{4}{3}x)+5

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