The 15th arrangement will have both a blue and red ribbon
Can you provide a visual so that it is easier to solve?
Answer:
-4/5
Step-by-step explanation:
To find the slope of the tangent to the equation at any point we must differentiate the equation.
x^3y+y^2-x^2=5
3x^2y+x^3y'+2yy'-2x=0
Gather terms with y' on one side and terms without on opposing side.
x^3y'+2yy'=2x-3x^2y
Factor left side
y'(x^3+2y)=2x-3x^2y
Divide both sides by (x^3+2y)
y'=(2x-3x^2y)/(x^3+2y)
y' is the slope any tangent to the given equation at point (x,y).
Plug in (2,1):
y'=(2(2)-3(2)^2(1))/((2)^3+2(1))
Simplify:
y'=(4-12)/(8+2)
y'=-8/10
y'=-4/5
Answer:
x = -5/3
Step-by-step explanation:
Hope this helps!
Best of luck!♥
Kate can travel 41.33 miles without exceeding her limit. This problem can be solved by using y = 2.25x + 7 linear equation with the "y" variable as the total cost that Kate must pay after she has traveled with the cab and the "x" variable as Kate's traveling distance. The equation has 7 for its constant value which is the $7 flat rate. We will find 41.33 miles as the traveling distance if we substituted the total cost with 100, which is the maximum amount that can be paid by Kate for the traveling purpose.
