Add the balance and allotment:
22.90 + 50.00 = 72.90
This is how much she can actually spend.
She spent 85.50.
Subtract the two:
85.50 - 72.90 = 12.60
Since she spent more than she actually could be balance would be a negative number.
The balance would be - $12.60
Answer:
y=1/2x-3
gradient = 1/2
also should satisfy the given coordinates
Answer:
22*1.06 = cost of meal with tax = 23.32
22*.20 = tip on the pre-tax cost = 4.40
Total = $27.72
Step-by-step explanation:
Both of these conditions must be true in order for the assumption that the binomial distribution is approximately normal. In other words, if
and
then we can use a normal distribution to get a good estimate of the binomial distribution. If either np or nq is smaller than 5, then a normal distribution wouldn't be a good model to use.
side note: q = 1-p is the complement of probability p
The right answer is Option C : 5
Step-by-step explanation:
Let,
The numerator of fraction = x
The denominator of a fraction is 10 more than its numerator.
![\frac{x}{x+10}](https://tex.z-dn.net/?f=%5Cfrac%7Bx%7D%7Bx%2B10%7D)
When 1/3 is added to this fraction,
![\frac{x}{x+10}+\frac{1}{3}](https://tex.z-dn.net/?f=%5Cfrac%7Bx%7D%7Bx%2B10%7D%2B%5Cfrac%7B1%7D%7B3%7D)
the resulting fraction’s denominator is three times the denominator of the original fraction its numerator is 15 less than its denominator
![\frac{3(x+10)-15}{3(x+10)}](https://tex.z-dn.net/?f=%5Cfrac%7B3%28x%2B10%29-15%7D%7B3%28x%2B10%29%7D)
Therefore, it becomes
![\frac{x}{x+10}+\frac{1}{3} = \frac{3(x+10)-15}{3(x+10)}](https://tex.z-dn.net/?f=%5Cfrac%7Bx%7D%7Bx%2B10%7D%2B%5Cfrac%7B1%7D%7B3%7D%20%3D%20%5Cfrac%7B3%28x%2B10%29-15%7D%7B3%28x%2B10%29%7D)
Taking LCM on left side
![\frac{3x+(x+10)}{3(x+10)}=\frac{(3x+30)-15}{3(x+10)}\\\\\frac{3x+x+10}{3(x+10)}=\frac{3x+30-15}{x(x+10)}\\\\\frac{4x+10}{3(x+10)}=\frac{3x+15}{3(x+10)}](https://tex.z-dn.net/?f=%5Cfrac%7B3x%2B%28x%2B10%29%7D%7B3%28x%2B10%29%7D%3D%5Cfrac%7B%283x%2B30%29-15%7D%7B3%28x%2B10%29%7D%5C%5C%5C%5C%5Cfrac%7B3x%2Bx%2B10%7D%7B3%28x%2B10%29%7D%3D%5Cfrac%7B3x%2B30-15%7D%7Bx%28x%2B10%29%7D%5C%5C%5C%5C%5Cfrac%7B4x%2B10%7D%7B3%28x%2B10%29%7D%3D%5Cfrac%7B3x%2B15%7D%7B3%28x%2B10%29%7D)
Multiplying both sides by 3(x+10)
![3(x+10)*\frac{4x+10}{3(x+10)}=\frac{3x+15}{3(x+10)}*3(x+10)\\4x+10=3x+15\\4x-3x=15-10\\x=5](https://tex.z-dn.net/?f=3%28x%2B10%29%2A%5Cfrac%7B4x%2B10%7D%7B3%28x%2B10%29%7D%3D%5Cfrac%7B3x%2B15%7D%7B3%28x%2B10%29%7D%2A3%28x%2B10%29%5C%5C4x%2B10%3D3x%2B15%5C%5C4x-3x%3D15-10%5C%5Cx%3D5)
The numerator of original fraction is 5.
The right answer is Option C : 5
Keywords: fraction, addition
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