Question

What volume would a container need to be to hold 0.750 mol of neon at 5.00 atm at 325 K? (R = 0.0820574 L*atm/(mol*K))

Answer 1

Answer:

$4.00\text{ L}$

Explanation:

Here, we want to get the volume of the container needed

From the ideal gas law:

$\begin{gathered} PV\text{ = nRT} \\ V\text{ = }\frac{nRT}{P} \end{gathered}$

where:

V is the volume of the container that we want to calculate

n is the number of moles of Neon which is 0.750 mol

R is the molar gas constant which is 0.0820574

T is the temperature at 325 K

P is the pressure at 5 atm

Substituting the values:

$V\text{ = }\frac{0.75\times0.0820574\times325}{5}\text{ = 4 L}$