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icang [17]
3 years ago
15

If the cardboard square has a light on it what do observe​

Chemistry
1 answer:
DaniilM [7]3 years ago
3 0

Answer:you observe the light?

Explanation:

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A device that sends electrical impulses to the heart to correct an irregular
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A. A pacemaker

Hope this helps!
6 0
2 years ago
a photon of light has a frequency of 3.5 x 10 to the 14th Hertz what is the wavelength of this light what color is this late
Oliga [24]

Wavelength relates to frequency as follows: λ=vf in which f is the frequency, v is the speed of light, and λ is the wavelength.

4 0
3 years ago
A rock is found to have a mass of 200 g and a volume of 100 ml. what is the rock's density?
GaryK [48]
Mass over volume
200 over100
2
4 0
3 years ago
838th
dangina [55]

Answer:

Different liquid

Explanation:

<em>The independent variable in the investigation is the different liquid given to the plants.</em>

<u>The independent variable in an experimental investigation is the variable that is supplied by the researcher which directly affects the main variable being measured during the investigation. In other words, the independent variable is a variable that directly affects the dependent variable.</u>

In this case, the dependent variable would be growth determining factors in plants such as height, biomass, number of leaves, etc. while the independent variable would be the different types of liquid given to the plants.

5 0
3 years ago
Potassium chloride is used as a substitute for sodium chloride for individuals with high blood pressure. Identify the limiting r
djyliett [7]

Answer:

* Limiting reagent: potassium.

* m_{Cl_2}^{excess}=2.47gCl_2

Explanation:

Hello,

In this case, the undergoing chemical reaction is:

2K(s)+Cl_2(g)\rightarrow 2KCl

In such a way, the reacting moles of chlorine are:

n_{Cl_2}=7.00g*\frac{1molCl_2}{70.9gCl_2}=0.0987molCl_2

Now, the amount of chlorine gas that would react with 5.00 g of potassium result:

n_{Cl_2}^{consumed}=5.00g*\frac{1molK}{39.1gK}*\frac{1molCl_2}{2molK}=0.0639molCl_2

Thus, the chlorine will be in excess and the potassium will be the limiting reagent. Therefore, the mass of excess chlorine turns out:

m_{Cl_2}^{excess}=(0.0987-0.0639)molCl_2*\frac{70.9gCl_2}{1molCl_2}=2.47gCl_2

Best regards.

4 0
3 years ago
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