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Evgen [1.6K]
3 years ago
14

Why is specific heat capacity more useful then heat capacity when comparing two materials

Chemistry
1 answer:
coldgirl [10]3 years ago
5 0

Answer:

Explanation:

Specific heat capacity can be defined as the heat required to raise the temperature of a unit mass of a substance by 1kelvin.

The heat capacity on the other hand, expresses the heat required to raise the temperature of  asubstance by 1kelvin.

When we use specific heat capacity, we are particular about the amount of heat that would be needed to actually cause a temperature change in a unit of a substance. This suggests that even if we don't have a complete substance, we can be sure that by knowing the mass of a unit of a body one can easily estimate how much heat is required to raise its temperature. The specific heat is fundamental in calculating the heat capacity of a body. Without the value of the specific heat, we cannot evalutate the heat capacity of a body.

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I need help solving a kinetics equation.
Lady bird [3.3K]

Answer:

what would the question be?

7 0
3 years ago
How are the sensory clues from watching a fire different from the sensory clues from watching a firefly?​
Mademuasel [1]

Answer:

watching a firefly is much different than watching a fire because watching a fire can make you hot and watching a firefly can make you happy

7 0
2 years ago
2. What is the name of the compound AIPO?
Andru [333]

Answer:

Aluminum phosphate

Explanation:

7 0
2 years ago
What is the empirical formula of propene CH3 CH2 CH2​
kiruha [24]

Answer:

<u>CH</u>

Explanation:

Molecular formula of propene : <u>C₃H₆</u>

Take the HCF of carbon and hydrogen atoms :

  • 3 = 3
  • 6 = 2 x 3

Then, we can write the formula as :

  • 3CH
  • This means there are 3 moles present

Empirical Formula :

  • Molecular Formula / No. of moles
  • C₃H₆ / 3
  • <u>CH</u>

<u></u>

The empirical formula of propene is <u>CH</u>

6 0
2 years ago
What is the freezing point of a solution of 498mL of water (solute) dissolved in 2.50 L of ethanol (solvent), C2H5OH? The densit
jok3333 [9.3K]

Answer:

Freezing T° of solution is -142.4°C

Explanation:

This excersise is about colligative properties, in this case freezing point depression,

ΔT = Kf . m . i

Where ΔT = Freezing T° of solvent - Freezing T° of solution

Kf = Cryoscopic constant

m = mol/kg (molality)

i = Number of ions dissolved.

Water is not ionic, so i = 1

Let's find out m.

We determine mass of water, by density

498ml . 1 g/mL = 498 g

We convert the mass of water to moles → 498 g . 1mol/18g = 27.6 moles

We determine mass of solvent by density

2500 mL . 0.789 g/mL = 1972.5 g

Notice, we had to convert L to mL to cancel units.

1 cm³ = 1 mL

We convert the mass from g to kg → 1972.5 g . 1kg /1000g = 1.97kg

We determine m = mol/kg → 27.6mol / 1.97kg = 13.9 m

Kf for ethanol is: 1.99 °C/m

Freezing T° for ethanol is: -114.6°C

We replace at formula: - 114.6°C - Freezing T° solution = 1.99 °C/m . 13.9 m . 1

- 114.6°C - Freezing T° solution = 27.8 °C

- Freezing T° solution  = 27.8°C + 114.6°C

Freezing T° Solution = - 142.4 °C

7 0
3 years ago
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