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Gelneren [198K]
1 year ago
4

I

Mathematics
1 answer:
MissTica1 year ago
3 0

The type of variation that describes each relationship include the following:

  1. Direct variation: the amount of time needed to mow a yard increases as the size of the yard increases.
  2. Indirect variation: the amount of time needed to drive from city A to city B decreases as the speed you are driving increases.
  3. Joint variation: the income of a worker who gets paid an hourly wage increases as the number of hours worked increases and increases as the salary rate increases.

<h3>What is an indirect variation?</h3>

An indirect variation simply refers to a type of proportional relationship in which a variable is inversely proportional to another variable. This ultimately implies that, an indirect variation represents two variables that are inversely proportional to each other, which means as one variable increases, the other variable decreases and vice-versa.

<h3>What is direct variation?</h3>

Direct variation refers to a type of proportional relationship in which a variable is directly proportional to another variable. This ultimately implies that, a direct variation represents two variables that are directly proportional to each other, which means as one variable increases, the other variable also increases and vice-versa.

Read more on variation here: brainly.com/question/16455054

#SPJ1

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The correct answer is

t = \frac{0.49-0.29}{\sqrt{\frac{(0.42)^2}{100} +}\frac{(0.29)^2}{100}  }

Step-by-step explanation:

To solve the question we note that the question involves a test statistic calculation given by

t = \frac{x_1-x_2}{\sqrt{\frac{s_1^2}{n_1} +}\frac{s_2^2}{n_2}  } Where

x₁ = Mean of sample 1

x₂ = Mean of sample 2

n₁ = Sample size of sample 1

n₂ = Sample size of sample 2

s₁ = Variance of sample 1

s₂ = Variance of sample 2

s₁ = ∑(x₁ - x₁')²/n₁,  s₂ = ∑(x₂ - x₂')²/n₂

The test statistic is a variable that is derived from a given data sample and is applied in hypothesis testing. The test statistic measures the available data against the expected value from the null hypothesis

With the given data, we have

t = \frac{0.49-0.29}{\sqrt{\frac{(0.42)^2}{100} +}\frac{(0.29)^2}{100}  }

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