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mihalych1998 [28]

4 years ago

8

6x=30 how do you solve

1 answer:

nadya68 [22]4 years ago

6 0

6x = 30
x = 30 / 6
x = 5

Hope I helped you :)

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The weights of college football players are normally distributed with a mean of 200 pounds and a standard deviation of 50 pounds

Feliz [49]

Answer:

0.3811 = 38.11% probability that he weighs between 170 and 220 pounds.

Step-by-step explanation:

When the distribution is normal, we use the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this question, we have that:

$\mu = 200, \sigma = 50$

Find the probability that he weighs between 170 and 220 pounds.

This is the pvalue of Z when X = 220 subtracted by the pvalue of Z when X = 170.

X = 220

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{220 - 200}{50}$

$Z = 0.4$

$Z = 0.4$ has a pvalue of 0.6554

X = 170

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{170 - 200}{50}$

$Z = -0.6$

$Z = -0.6$ has a pvalue of 0.2743

0.6554 - 0.2743 = 0.3811

0.3811 = 38.11% probability that he weighs between 170 and 220 pounds.

6 0

4 years ago

Divide 75 by -25.<br> 12

enot [183]

Answer: 6.25

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

I. The airport branch of a car rental company maintains a fleet of 50 SUVs. The interarrival time between requests for an SUV is

rosijanka [135]

Answer:

20

Step-by-step explanation:

For the computation of the average number of SUVs parked in the company's lot first it is required to compute the utilization which is shown below:-

$Utilization = \frac{p}{a\times m}$

where p indicates activity time which is equal to 3 days = 72 hours

a indicates an interarrival time which is equal to 2.4

m indicates the number of servers which is equal to 50

now we will put the values into the above formula

$Utilization = \frac{72}{2.4\times 50}$

After solving the above equation we will get

u = 0.6

or

60%

now, the average cars parked in the company's lot is

$Average\ cars = 50 - 60\%\times 50$

= 50 - 30

= 20

4 0

4 years ago

5. Evaluate each expression when d = 5. <br>a) 60<br>c) d + 1<br>b) 50 - 1<br>d) 3(d + 2)

Andrews [41]

Answer:

ok so c is 5 + 1. that is 6. and d is 3 x 5 which is 15 + 6, so 21. I dont know about a or b though, sorry.

Step-by-step explanation:

6 0

3 years ago

PLZ I NEED RIGHT ANSWERS NOW

liraira [26]

Here’s the answer
(x-8)^2 + y^2 = r^2

3 0

3 years ago