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3 years ago

Please help, I'm too indifferent to math to actually have an opinion.

Mathematics

2 answers:

labwork [276]3 years ago

5 0

Answer:

Step-by-step explanation:

Math is not horrible, it is simply necessary. I prefer to think of it as weightlifting for your brain. For instance, calculus you will probably never use in your day to day life. But it is an exercise for your brain to become stronger at figuring out problems faster. Math is not especially important to my family or friends, none of them are math professors or want to become a mathematician. I think that is because they share most of the views I do.

Olin [163]3 years ago

3 0

Math to me is very complicated. I know that I need it in life, but when have you ever needed to find the square root of the distance from the sun to mars on a normal day-to-day basis? But jokes aside, I know that I do math without thinking about it. It is important, even for the jobs that you would think that you would NEVER need it (even English teachers do it, haha.) Overall, math is kinda iffy. In my opinion, you can't live with it, but you <u>really</u> can't live without it.

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A walk-in medical clinic believes that arrivals are uniformly distributed over weekdays (Monday through Friday). It has collecte

allsm [11]

Answer:

The degrees of freedom are given by;

$df =n-1= 5-1=4$

The significance level is 0.1 so then the critical value would be given by:

$F_{cric}= 7.779$

If the calculated value is higher than this value we can reject the null hypothesis that the arrivals are uniformly distributed over weekdays

Step-by-step explanation:

For this case we have the following observed values:

Mon 25 Tue 22 Wed 19 Thu 18 Fri 16 Total 100

For this case the expected values for each day are assumed:

$E_i = \frac{100}{5}= 20$

The statsitic would be given by:

$\chi^2 = \sum_{i=1}^n \frac{(O_i-E_i)^2}{E_i}$

Where O represent the observed values and E the expected values

The degrees of freedom are given by;

$df =n-1= 5-1=4$

The significance level is 0.1 so then the critical value would be given by:

$F_{cric}= 7.779$

If the calculated value is higher than this value we can reject the null hypothesis that the arrivals are uniformly distributed over weekdays

5 0

3 years ago

PLEASE HELP ASAP I WILL MAKE YOU THE BRAINLEST

Alex

Answer:

$1,272

Step-by-step explanation:

Just add 1,200 (how much she borrowed) and 6/100*1200 (6 percent of 1200) and you will get the answer of $1,272

7 0

4 years ago

The two shorter sides of a triangle are 9 and 12. what is a possible length to make length of the third side to make the triangl

Paraphin [41]

The two shorter sides of triangle are 9 and 12. what is a possible length to make length of the third side to make the triangle acute with acuteT

6 0

3 years ago

WORTH 20 POINTS HELP

vfiekz [6]

Below represents the proof that the quadrilateral QRST is a parallelogram

<h3>How to prove that QRST is a parallelogram?</h3>

The coordinates are given as:

Q = (-1,-1)

R = (2,9)

S = (-4,5)

T = (-7,-5)

Calculate the length of each side using:

$d = \sqrt{(x_2 -x_1)^2 + (y_2 -y_1)^2}$

So, we have:

$QR = \sqrt{(-1 - 2)^2 + (-1 -9)^2} = \sqrt{109}$

$RS = \sqrt{(-4 - 2)^2 + (5 - 9)^2} = \sqrt{52}$

$ST = \sqrt{(-7 + 4)^2 + (-5 - 5)^2} = \sqrt{109}$

$TQ = \sqrt{(-7 + 1)^2 + (-5 + 1)^2} = \sqrt{52}$

The above computations show that opposite sides are equal.

Next, we determine the slope of each side using:

$m = \frac{y_2 -y_1}{x_2 -x_1}$

So, we have:

$QR = \frac{9 + 1}{2 + 3} = \frac{10}3$

$RS = \frac{5-9}{-4 - 2} = \frac{2}3$

$ST = \frac{5+5}{-4 + 7} = \frac{10}3$

$TQ = \frac{-5+1}{-7 + 1} = \frac{2}3$

The above computations show that opposite sides are parallel, because they have equal slope

Hence, the quadrilateral QRST is a parallelogram