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Masteriza [31]
1 year ago
9

81. a baseball is hit straight up and is caught by the catcher 2.0 s later, at the same height at which it left the bat. the max

imum height of the ball during this interval is: a) 4.9 m b) 7.4 m c) 12.4 m d) 19.6 m
Physics
1 answer:
andrew-mc [135]1 year ago
7 0

The maximum height of the ball during this interval is 4.9 m (Option A)

<h3>How to determine the time to reach maximum height</h3>

The time taken to reach the maximum height can be obtained as follow:

  • Time for the entire trip (T) = 2 s
  • Time to reach maximum height (t) = ?

T = 2t

2 = 2t

Divide both side by 2

t = 2 / 2

t = 1 s

<h3>How to determine the maximum height reached by the ball</h3>

The maximum height reached by the ball can be obtained as follow:

  • Acceleration due to gravity (g) = 9.8 m/s²
  • Time to reach maximum height (t) =?
  • Maximum height (h) =?

h = ½gt²

h = ½ × 9.8 × 1²

h = ½ × 9.8 × 1

h = 4.9 m

Thus, the maximum height reached by the ball is 4.9 m (Option A)

Learn more about motion under gravity:

brainly.com/question/22719691

#SPJ1

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