What is magnification

Starting from the front door of your ranch house, you walk 50.0 m due east to your windmill, and then you turn around and slowly

Hunter-Best [27]

Answer:

Average velocity

$v=\frac{d}{t}\\ v=\frac{10m}{70s}\\v=.1428 \frac{m}{s}$

Average speed,

$S=\frac{D}{t}\\ S=\frac{90}{70}\\ S=1.29\frac{m}{s}$

Explanation:

(a)Average velocity

We have to find the average velocity. We know that velocity is defined as the rate of change of displacement with respect to time.

To find the average velocity we have to find the total displacement.

since displacement along east direction is 50m

and displacement along west=40m

so total displacement,

$d=50m-40m\\d=10m$

total time,

$t=28 s+42 s\\t=70 s$

therefore, average velocity

$v=\frac{d}{t}\\ v=\frac{10m}{70s}\\v=.1428 \frac{m}{s}$

(b)Average Speed:

Average speed is defined as the ratio of total distance to the total time

it means

Average speed= total distance/total time

here total distance,

$D= 50m+40m\\D=90m$

and total time,

$t= 28s+40s\\t=70s$

therefore,

Average speed,

$S=\frac{D}{t}\\ S=\frac{90}{70}\\ S=1.29\frac{m}{s}$

8 0

3 years ago

Decide whether the attribute describes Earth, Venus, or both Earth and Venus.

masha68 [24]

1). both

2). Venus

3). Venus catastrophically; Earth too but much less.

4). Earth

5). Earth

6). Venus (It would be pretty hard for US to mistake Earth for a star.)

3 0

3 years ago

Read 2 more answers

Calculate the electric charge of the glass ball

-Dominant- [34]

Answer:

As per Coulomb's law we know that force between two charges is given as

F = \frac{kq_1q_2}{r^2}F=

r

2

kq

1

q

2

here we know that

q_1 = 2.5 \times 10^{-6} Cq

1

=2.5×10

−6

C

q_2 = -5.0 \times 10^{-6} Cq

2

=−5.0×10

−6

C

r = 0.0050 mr=0.0050m

now from above formula we will have

F = \frac{(9 \times 10^9)(2.5 \times 10^{-6})(5 \times 10^{-6})}{(0.0050)^2}F=

(0.0050)

2

(9×10

9

)(2.5×10

−6

)(5×10

−6

)

F = 4500 NF=4500N

so they will attract towards each other as they are opposite in nature with force F = 4500 N

4 0

3 years ago

gravity on the surface of the Moon is only 1/6 as strong as gravity on the earth what is the weight of a 31 kg object on the ear

Effectus [21]

Answer:

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Explanation:

7 0

2 years ago

A uniform electric field of magnitude 442 N/C pointing in the positive x-direction acts on an electron, which is initially at re

Brums [2.3K]

A) The electric field is constant and in the same direction as the electron's displacement, so the work done is given by:

W = Fd

W = work, F = electric force, d = displacement

The electric force on the electron is given by:

F = Eq

F = electric force, q = electron charge

Substitute F:

W = Eqd

Given values:

E = 442N/C, q = 1.6×10⁻¹⁹C, d = 3.50×10⁻²m

Plug in and solve for W:

W = 442(1.6×10⁻¹⁹)(3.50×10⁻²)

W = 2.48×10⁻¹⁸J

B) The electric field does work to move the electron. Apply the conservation of energy and you'll see that the electron's potential energy loss is equal to the work done by the field in moving the electron.

The electric potential energy change is -2.48×10⁻¹⁸J

C) Apply the work-energy theorem; the electron's kinetic energy equals the work done on it by the field.

KE = 0.5mv² = W

m = electron mass, v = velocity, W = work

Given values:

W = 2.48×10⁻¹⁸J, m = 9.11×10⁻³¹

Plug in and solve for v:

0.5(9.11×10⁻³¹)v² = 2.48×10⁻¹⁸

v = 2.33×10⁶m/s

3 0

3 years ago