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Lera25 [3.4K]
4 years ago
5

What is magnification

Physics
1 answer:
il63 [147K]4 years ago
5 0
The action or process of magnifying something or being magnified, especially visually. Hope this helped
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How does electric force depend on the amount of charge and the distance between charges
Gennadij [26K]
<h2> F = k×\frac{q1q2}{r2}</h2>

Explanation:

  • The attractive or repulsive forces which act between any two charged species is an electric force.
  • The electric force depends on the distance between the charged species and the amount of charge which can be calculated by the formula given as follows  

    F = k×\frac{q1q2}{r2}

where, K is coulombs constant, which is equal to -                                  9 x10^9 Nm^2/C^2.

  • The unit for K is newtons square meters per square coulombs.
  • This is known as Coulomb's Law.
6 0
3 years ago
When placed in direct sunlight, which an object will absorb the most visible light energy
Vikentia [17]
I would guess anything that is black? black absorbs there most light energy. that's is why a black car in the sun will always be hotter inside than a white car.
3 0
4 years ago
An automobile steering wheel is shown. What is the ideal mechanical advantage? If the AMA is 8, what is the efficiency of the st
Mars2501 [29]

1. Ideal Mechanical Advantage (IMA): 9

Explanation:

For a wheel and axle system like the steering wheel, the IMA is given by:

IMA=\frac{r_w}{r_a}

where

r_w is the radius of the wheel

r_a is the radius of the axle

For the steering wheel of the problem, we see that r_w = 18 cm and r_a=2 cm, so the IMA is

IMA=\frac{18 cm}{2 cm}=9


2. Efficiency: 88.9%

Explanation:

The efficiency of a system is defined as the ratio between the AMA (actual mechanical advantage) and the IMA:

\eta=\frac{AMA}{IMA}\cdot 100

In this problem, AMA=8 and IMA=9, so the efficiency is

\eta=\frac{8}{9}\cdot 100=88.9\%


6 0
4 years ago
Which statement best compares potential and kinetic energy?
Eddi Din [679]

Answer:

I think option 1st is correct

lf it is wrong I apologise

HAVE A NICE DAY

8 0
3 years ago
Read 2 more answers
A 13500 kg jet airplane is flying through some high winds. At some point in time, the airplane is pointing due north, while the
Mekhanik [1.2K]

Answer

given,

mass of the jet airplane = 13500 kg

Force on the plane = 35700 N due north

force from wind  = 15300 N in direction 80.0° south of west.

Force = 35700 \vec{j} N

force by wind = 15300(-cos \theta \vec{i}-sin \theta \vec{j}) N

                       = 15300(-cos 80^0 \vec{i}-sin 80^0 \vec{j}) N

net force on the jet airplane(ma)

          m a = 35700 \vec{j} + 15300(-cos 80^0 \vec{i}-sin 80^0 \vec{j})

          \vec{a} = \dfrac{35700}{13500} \vec{j} + \dfrac{15300}{13500}(-cos 80^0 \vec{i}-sin 80^0 \vec{j})

          \vec{a} = 2.64\vec{j} -0.197 \vec{i} - 1.116 sin 80^0 \vec{j})

           \vec{a} = -0.197 \vec{i} + 1.524 \vec{j}

a = \sqrt{-0.197^2+1.524^2}

a = 1.54 m/s²

\theta = tan^{-1}(\dfrac{-1.524}{0.197})

\theta = -82.63^0

3 0
3 years ago
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