Wait like the equations, or is there an actual question?
Equations are
Final velocity (Vf) = Initial velocity (Vi) + Acceleration (a) x Time (t)
Acceleration (a) = (Final velocity [Vf] - initial velocity [Vi]) divided by Time (t)
Force (f) = Mass (m) x Acceleration (a)
(Short version)
Vf = Vi + a(t)
a = (Vf - Vi) divided by t
F = m x a
Answer:
a) d = 30.79 m
, b) θ = -22.4°
, θ = 22.4 South of East
Explanation:
The easiest way to solve problems with vectors is to use their components, for this the East-West direction coincides with the x-axis and the North-South direction coincides with the y-axis
Let's use the index for / Ricardo and the index for Jane, let's break down the displacements
Richard
X axis
x₁ = 26.0 sin (60)
x₁ = -22.52 m
Y Axis
y₁ = 26.0 cos 60
y₁ = 13 m / s
Jane
X axis
x₂ = 16.0 cos (180 +30)
x₂ = -13.85 m
Y Axis
y₂ = 16.0 sin (180 + 30)
y₂ = - 8.0 m
Now we can use Pythagoras' theorem to find the distance between them
d = √ [(x₂ -x₁)² + (y₂ -y₁)²]
d = √ [(-13.85 + 22.52)² + (-8 -13)²]
d = 30.79 m
Let's use trigonometry to enter the address
tan θ = Δy / Δx
θ = tan⁻¹ Δy / Δx
θ = tan⁻¹ (-13.85 + 22.52) / (-8 - 13)
θ = tan⁻¹ (-8.67 / 21)
θ = -22.4°
The negative sign indicates that the angle is measured from the axis clockwise.
In the form of cardinal s point is
θ = 22.4 South of East
Answer:
The deflection of the spring is 34.56 mm.
Explanation:
Given that,
Diameter = 10 mm
Number of turns = 10


Load = 200 N
We need to calculate the deflection
Using formula of deflection

Put the value into the formula


Hence, The deflection of the spring is 34.56 mm.
I'm pretty sure it's true. Hope it helps!