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3 years ago

Which of the following best describes this Image?

Physics

2 answers:

Orlov [11]3 years ago

7 0

Answer: 4. Good accuracy

Explanation: Considering the center red dot to be the target and the dark dots to be the patch of the attempted targets.

The given figure has all the three attempts close enough to the target on the penultimate circular white patch, therefore we can say that the figure defines a good accuracy.

Accuracy is the degree of closeness to the targeted value (or spot, as here the case is) of an attempt (or a series of attempts) made.

Precision is defined as the degree of closeness of a series of attempts made i.e. the attempts taken must be close to each other having lesser deviation be it far from the target or closer to the target it does not matters.

ratelena [41]3 years ago

5 0

Good precision because he is hitting the same spot 3 times but we don't know if he is accurate. SO the answer is 2

You might be interested in

What is the density of the solid given that its mass is 200

alina1380 [7]

Answer:

a) 2cm³

b) 100 g/cm³

Explanation:

a- 9-7= 2cm³

b- 200 divided by 2= 100 g/cm³

Hope this helps... correct me if i'm wrong

7 0

3 years ago

A 10000 N net force is accelerating a car at a rate if 5.5 m/s^2. What is the cars’s mass?

lianna [129]

Answer:

1800 kg

Explanation:

Newton's second law:

F = ma

10000 N = m (5.5 m/s²)

m ≈ 1800 kg

8 0

3 years ago

Read 2 more answers

A pickup truck and a hatchback car start at the same position. If the truck is moving at a constant 33.2m/s and the hatchback ca

love history [14]

Answer:

The pickup truck and hatchback will meet again at 440.896 m

Explanation:

Let us assume that both vehicles are at origin at the start means initial position is zero i.e. $s_{o}$ = 0. Both the vehicles will cross each other at same time so we will make equations for both and will solve for time.

Truck:

$v_{i}$ = 33.2 m/s, a = 0 (since the velocity is constant), $s_{o}$ = 0

Using $s =s_{o}+v_{i}t+1/2at^{2}$

s = 33.2t .......... eq (1)

Hatchback:

$a=5m/s^{2}$ , $v_{i}$ = 0 m/s (since initial velocity is zero), $s_{o}$ = 0

Using $s =s_{o}+v_{i}t+1/2at^{2}$

putting in the data we will get

$s=(1/2)(5)t^{2}$

now putting 's' value from eq (1)

$2.5t^{2}-33.2t=0$

which will give,

t = 13.28 s

so both vehicles will meet up gain after 13.28 sec.

putting t = 13.28 in eq (1) will give

s = 440.896 m

So, both vehicles will meet up again at 440.896 m.

7 0

3 years ago

Read 2 more answers

Newton’s second law of motion can also be described as _____.

anzhelika [568]

Answer:

F=ma

Explanation:

The Newton's laws of motion tries to explain the how bodies behave and the energy changes when theys are in motion. For the 3 of them to hold, the bodies must be moving in a straight line and with constant velocity.

The second one states that, "the change of momentum of a moving body is directly proportional to the force producing it and it takes place to the direction of force."

From the choices given, the appropriate answer is F=ma

3 0

3 years ago

Can classical physics be used to accurately describe a satellite moving at a speed of 7500 m/s? explain why or why not.

gogolik [260]

The classical physics works on the Newton's laws of motion. It is applicable on heavenly bodies which are governed by the gravitational force. On the other hand, Quantum Physics is applicable for very low mass and sized bodies like electron, protons etc. The classical physics would accurately describe the motion of satellite moving with speed 7500 m/s using the following formula:

$r=\frac {GM}{v^{2}}$

where G is the gravitational constant, M is the mass of the planet and v is the orbital speed. Then radius of the orbit can be described by this formula.

3 0

3 years ago